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Vlada [557]
3 years ago
8

Summer day camp is about to begin. Today there are 132 boys signed up and 219 total children signed up. How many more boys than

girls are signed up for camp?
Mathematics
2 answers:
Soloha48 [4]3 years ago
8 0
45 more boys are signed up than girls
Gre4nikov [31]3 years ago
6 0
Somebody camp is about to begin today there is 101
You might be interested in
1) State the amplitude, period, phase shift, vertical shift and graph
bogdanovich [222]

Answer:

See answers and explanations below (along with a visual graph)

Step-by-step explanation:

For the function y=acos(b(x+c))+d:

Amplitude: |a|

Period: \frac{2\pi}{|b|}

Phase shift: \frac{-c}{b}

Vertical shift: d

Therefore, for y=2cos(\frac{2}{3}(\theta+\pi))-1:

Amplitude: |a|=|2|=2, which is 2 units above and below the midline (see d)

Period: \frac{2\pi}{|b|}=\frac{2\pi}{|\frac{2}{3}|}=\frac{2\pi}{\frac{2}{3}}=3\pi, so the cycle will repeat every 3π units

Phase shift: \frac{-c}{b}=\frac{-\frac{2\pi}{3} }{\frac{2}{3} }=-\pi, or π units to the left

Vertical shift: d=-1, or 1 unit down

3 0
3 years ago
Koby can work about 22 math problems in 30 minutes. At this rate how many math problems can Koby work in 3 hours
Murrr4er [49]
132 problems because...

there are six 30 minutes in 3 hours so you would multiply 22 with 6 to get 132 
(22*6=132)
4 0
3 years ago
Read 2 more answers
One afternoon, 27 people withdraw $100 from an ATM. What was the overall change in the amount of money in the machine?​
Usimov [2.4K]

Answer:

The change is a decrease of $2700.

Step-by-step explanation:

Given

Total Number of people = 27

Amount each person withdrew = $100

The total withdrawn amount by 27 people = 100 × 27

                                                                       = $2700

Let M be the amount of money in the ATM at the beginning.

As $2700 was drawn from the ATM, therefore, the change the amount of money in the machine will be:

  • M - 2700

It means the change is a decrease of $2700.

3 0
3 years ago
The bottom of Ignacio's desktop is 74.5cm from the floor. Ignacio's sits in his adjustable chair, and the tops of his legs are 4
dsp73

Answer:

Ignacio can make 5 clockwise rotations.

Step-by-step explanation:

Given that the Ignacio's legs are already at a height of 49.3cm and each rotation of the chair knob raises his legs another 4.8cm, we can set up an inequality to determine the number of rotations Ignacio could make without his legs touching the desk, which is at a height of 74.5cm:

4.8r + 49.3 < 74.5  where 'r' is equal to the number of rotations

The sum of the Ignacio's original leg height plus the amount of height increased from the rotations of the know must be less than 74.5 in order for his legs not to touch.  Now, solve for 'r':

Subtract 49.3 from both sides:  4.8r + 49.3 - 49.3 < 74.5 - 49.3 or 4.8r < 25.2

Divide 4.8 from both sides:  4.8r/4.8 < 25.2/4.8 or  r < 5.25

Since the number of rotations must be less than 5.25, he can make 5 complete rotations.  

6 0
3 years ago
Simplify the expression 2√ 20 − 3√ 7 − 2√ 5 + 4√ 63 .
earnstyle [38]

Answer:

The simplified form is,

\boxed{\boxed{6\sqrt{5}+9\sqrt{7}}}

Step-by-step explanation:

The given expression is,

=2\sqrt{20}-3\sqrt{7}+2\sqrt{5}+4\sqrt{63}

=2\sqrt{4\times 5}-3\sqrt{7}+2\sqrt{5}+4\sqrt{9\times 7}

=2(\sqrt{4}\times \sqrt{5})-3\sqrt{7}+2\sqrt{5}+4(\sqrt{9}\times \sqrt{7})

=2(2\times \sqrt{5})-3\sqrt{7}+2\sqrt{5}+4(3\times \sqrt{7})

=4\sqrt{5}-3\sqrt{7}+2\sqrt{5}+12\sqrt{7}

=4\sqrt{5}+2\sqrt{5}+12\sqrt{7}-3\sqrt{7}

=6\sqrt{5}+9\sqrt{7}

8 0
4 years ago
Read 2 more answers
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