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faust18 [17]
4 years ago
11

Convert 4 into a fraction

Mathematics
1 answer:
harina [27]4 years ago
4 0

Answer: 4/1

Step-by-step explanation:

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Help me with this please
nalin [4]
This is incorrect. X can be negative, making the expression on the left less than 0. If x were -10, then:
3 x -10 + 1 > 0
-30 + 1 > 0
-29 > 0
Is NOT true.
5 0
3 years ago
We're working with single variable equations and I'm okay at them, but I'm rusty when it comes to using it with fractions. If an
jasenka [17]

Answer: v=-18/5

Step-by-step explanation:

Assuming you want to solve for v, we need to use our algebraic properties.

\frac{v}{3}+2=\frac{4}{5}                 [subtract both sides by 2]

\frac{v}{3}=-\frac{6}{5}                    [multiply both sides by 3]

v=-\frac{18}{5}

Now, we know that v=-18/5.

3 0
3 years ago
Write -14 as a decimal number and a fraction
Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

-14 = -14/1 = - 14.0

5 0
3 years ago
a garden plot is to contain 240 sq. ft. if its length is to be 3 times its width,what should its dimensions be?
SOVA2 [1]
240 ft^2 = L X W
240 = 3W x W
240 = 3W^2
W = 8.94427 ft
L = 3W = 3(8.94427)
L = 26.8328 FT
8 0
3 years ago
A geometric sequence is defined by the general term tn = 75(5n), where n ∈N and n ≥ 1. What is the recursive formula of the sequ
andreyandreev [35.5K]
The correct answer is C) t₁ = 375, t_n=5t_{n-1}.

From the general form,
t_n=75(5)^n, we must work backward to find t₁.

The general form is derived from the explicit form, which is
t_n=t_1(r)^{n-1}.  We can see that r = 5; 5 has the exponent, so that is what is multiplied by every time. This gives us

t_n=t_1(5)^{n-1}

Using the products of exponents, we can "split up" the exponent:
t_n=t_1(5)^n(5)^{-1}

We know that 5⁻¹ = 1/5, so this gives us
t_n=t_1(\frac{1}{5})(5)^n
\\
\\=\frac{t_1}{5}(5)^n

Comparing this to our general form, we see that
\frac{t_1}{5}=75

Multiplying by 5 on both sides, we get that
t₁ = 75*5 = 375

The recursive formula for a geometric sequence is given by
t_n=t_{n-1}(r), while we must state what t₁ is; this gives us

t_1=375; t_n=t_{n-1}(5)

3 0
3 years ago
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