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umka21 [38]
3 years ago
8

WILL AWARD BRAINLIEST! HELP ME OUT PLESSE! I NEED HELP WITH THIS!

Chemistry
2 answers:
marin [14]3 years ago
8 0

Answer:

LiOH (aq) + VCl3(aq) ---> LiCl(aq) + V(OH)3(s) - unbalanced

3LiOH (aq) + VCl3(aq) ---> 3LiCl(aq) + V(OH)3(s) - balanced

3Li+OH- (aq) + V3+(Cl-)3(aq) ---> 3Li+Cl-(aq) + V3+(OH-)3(s) - showing ions

3Li+(aq) + 3OH- (aq) + V3+(aq) + 3Cl-(aq) ---> 3Li+(aq) + 3Cl-(aq) + V3+(OH-)3(s) (some courses don't show the charges in insoluble ionic compounds - so V(OH)3(s)) - Showing soluble ionic compounds as separate ions.

3OH- (aq) + V3+(aq) ---> V3+(OH-)3(s) (or V(OH)3(s)) - without spectator ions

Explanation:

i don't know if this is right ore not but i hope this helps even if it is just a little bit sorry if this does not help i truly apologize

puteri [66]3 years ago
5 0

Answer:

What is the complete ionic equation? (answer:a molecular equation that separates the molecules into their ion forms. )

What is the net ionic equation? (answer: he net ionic equation is the chemical equation that shows only those elements, compounds, and ions that are directly involved in the chemical reaction. )

What are the spectator ion? ( answer: Ions that are not changed in the reaction)

Explanation:

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Which property is true for metals
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Does the hydrogen molecule obey the octet rule?
Alja [10]

Explanation:

Hydrogen does not obey the octet rule. Boron does not always

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6 0
3 years ago
Sulfonation of benzene has the following mechanism: (1) 2 H2SO4 ⇌ H3O+ + HSO4− + SO3 [fast] (2) SO3 + C6H6 → H(C6H5+)SO3− [slow]
ziro4ka [17]

Question is incomplete, complete question is as follows :

Complete Question : .Sulfonation of benzene has the following mechanism:

(1) 2 H2SO4 ⇌ H3O+ + HSO4− + SO3

[fast]

(2) SO3 + C6H6 → H(C6H5+)SO3−

[slow]

(3) H(C6H5+)SO3− + HSO4− → C6H5SO3− + H2SO4

[fast]

(4) C6H5SO3− + H3O+ → C6H5SO3H + H2O

[fast]

write the overall rate law for the initial rate of the reaction as a fraction.

Rate=k(________/_________)

Answer:

The overall rate law for the initial reaction is = k_{overall} [H_{2}SO_{4}]^{2} [C_{6}H_{6}]

Explanation :

Frist of all, all the common terms are cancelled out and written the overall reaction.

As we know that the rate depednant step is the slowest step of the reaction, rate law is :

                        rate = k_{2} [SO_{3}][C_{6}H_{6}]

But the problem is that SO3 cannot be written in the overall rate law because it is an intermediate.

Rate law for synthesis of S03 is as follows :

                       rate = k_{1}[H_{2}SO_{4}]^{2}

Hence when we substitute equation 2 in equation one,

                   Rate comes out to be =  k_{overall} [H_{2}SO_{4}]^{2} [C_{6}H_{6}]

6 0
3 years ago
A white rooster mates with a black hen. The offspring is gray in color. What is this phenomenon called?
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Answer:

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Explanation:

4 0
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