Question

A 9.38 microFarad capacitor is measured to have a reactance of 260.0 Ohm. At what frequency (in Hz) is it being driven?

Answer 1

Answer:

The frequency is 65.25 Hz.

Explanation:

Given that,

Capacitor = 9.38 μF

Reactant = 260.0 ohm

We need to calculate the frequency

Using formula of reactant

$X_{c}=\dfrac{1}{2\pi fC}$

Where, f = frequency

C = capacitor

$X_{c}$ =reactant

Put the value in to the formula

$260.0=\dfrac{1}{2\times\pi\times f\times9.38\times10^{6}}$

$f=\dfrac{1}{2\times\pi\times9.38\times10^{-6}\times260.0}$

$f=65.25\ Hz$

Hence, The frequency is 65.25 Hz