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alexira [117]
3 years ago
10

Suppose the mass of a fully loaded module in which astronauts take off from the Moon is 1.0 x 10^4 kg. The thrust of its engines

is 3.0 x 10^4N. Calculate the magnitude of acceleration in a vertical takeoff from the Moon with two significant figures. (a) 6.8 m/s^2 (b) 4.7 m/s^2 (c) 1.7 m/s^2 (d) 1.3 m/s^2
Physics
1 answer:
Artemon [7]3 years ago
4 0

Answer:

The right option is (d) 1.3 m/s^2

Explanation:

From the mass of the lunar module and the force printed by the engines I can obtain the acceleration that they produce:

F= m × a ⇒ a= (30000 kg × (m/s^{2}) ) / (10000kg) = 3 (m/s^{2})

This acceleration has an upward direction, and the gravitational acceleration of the moon has a downward direction, opposite to the first, so they are subtracted and the resulting acceleration will be:

Amoon= 1.6249  (m/s^{2})

Atotal=  3 (m/s^{2}) - 1.6249  (m/s^{2}) = 1.3751 (m/s^{2})

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2 years ago
A 180 g model airplane charged to 18 mC and traveling at 2.2 m/s passes within 8.6 cm of a wire, nearly parallel to its path, ca
viva [34]

Answer:

a=0.2*10^{-5}g

Explanation:

From the question we are told that:

Mass M=180=>0.18kg

Charge Q=18mC=18*10^-^3C

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Current I=30A

Generally the equation for Magnetic Field of Wire B is mathematically given by

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Generally the equation for Force on the plane F is mathematically given by

 F=qvB

Therefore

 ma=qvB

 a=\frac{qvB}{m}

 a=\frac{18*10^{-5}83.4*6.978*10^{-5}}{0.18kg}

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Therefore in Terms of g's

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8 0
2 years ago
You need to fill a basketball with air to play with it. You know that your pump expels air at a velocity of 6 cm/s. You know tha
Scrat [10]

Answer:

The diameter of the needle is <u>4.675 cm</u>.

Explanation:

Given:

Volume flow rate is, \dot V=103\ cm^3

Velocity of air expelled by pump is, v=6\ cm/s

Let the area of the needle be 'A' cm² and the diameter be 'd' cm.

We know that, volume flow rate of the air expelled by pump is given as the product of the needle's area and velocity of air flowing through that area.

Therefore, volume flow rate is given as:

\dot V=A\times v\\\\103=A\times 6\\\\6A=103\\\\A=\frac{103}{6}\ cm^2

Now, considering the needle to be circular, area of the needle can be written as:

A=\frac{\pi}{4}\times d^2\\\\\frac{103}{6}=\frac{\pi}{4}\times d^2\\\\d^2=\frac{103\times 4}{6\pi}\\\\d=\sqrt{\frac{103\times 4}{6\pi}}\\\\d=4.675\ cm

Therefore, the diameter of the needle is 4.675 cm.

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3 years ago
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3 years ago
A wave has a frequency of 450 Hz and a wave length of 00.52 m what is the speed of the wave?
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4 0
3 years ago
Read 2 more answers
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