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alexira [117]
3 years ago
10

Suppose the mass of a fully loaded module in which astronauts take off from the Moon is 1.0 x 10^4 kg. The thrust of its engines

is 3.0 x 10^4N. Calculate the magnitude of acceleration in a vertical takeoff from the Moon with two significant figures. (a) 6.8 m/s^2 (b) 4.7 m/s^2 (c) 1.7 m/s^2 (d) 1.3 m/s^2
Physics
1 answer:
Artemon [7]3 years ago
4 0

Answer:

The right option is (d) 1.3 m/s^2

Explanation:

From the mass of the lunar module and the force printed by the engines I can obtain the acceleration that they produce:

F= m × a ⇒ a= (30000 kg × (m/s^{2}) ) / (10000kg) = 3 (m/s^{2})

This acceleration has an upward direction, and the gravitational acceleration of the moon has a downward direction, opposite to the first, so they are subtracted and the resulting acceleration will be:

Amoon= 1.6249  (m/s^{2})

Atotal=  3 (m/s^{2}) - 1.6249  (m/s^{2}) = 1.3751 (m/s^{2})

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Answer:

Using the given values

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A proton is initially moving west at a speed of 1.10 106 m/s in a uniform magnetic field of magnitude 0.281 T directed verticall
kifflom [539]

Answer:

so here it will move in circle with radius 4.06 cm

Explanation:

As we know that proton is moving towards west while the magnetic field is vertically upwards

So here the force on the proton must be perpendicular to the velocity

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since force is perpendicular to the velocity so here it must be centripetal force

here we have

\frac{mv^2}{R} = qvB

so we have

R = \frac{mv}{qB}

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Gravitational Force: Two small objects, with masses m and M, are originally a distance r apart, and the magnitude of the gravita
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F is proportional to the inverse square of r:

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k₁ = 2M/M = 2

Calculate the scaling factor of F due to the change in m:

k₂ = 2m/m = 2

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Fk₁k₂k₃

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Mass = density • volume

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