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3 years ago

A student with a mass of 52 kg, starts from rest and travels down a 2 m slide. What is

Physics

1 answer:

Leya [2.2K]3 years ago

3 0

Answer:

https://www.ux1.eiu.edu/~cfadd/1350/Hmwk/Ch08/Ch8.html

Explanation:

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¿Qué tiempo realiza un avión de la Cd. de México a Cancún, si la distancia entre ambos es de 1608.9Km y el avión viaja a una rap

Leya [2.2K]

I can help you with that if you translate to English

3 0

3 years ago

Long Snorkel: Inhalation of a breath occurs when the muscles surrounding the human lungs move to increase the volume of the lung

Mila [183]

Answer:

h = 0.362 m

Explanation:

The pressure equation with depth is

P₂ = $P_{atm}$ +ρ g h

The gauge pressure is

P2 - $P_{atm}$ = ρ g h

This is the pressure that muscles can create

P₂ - $P_{atm}$ = 3740 Pa

But still the person needs a small pressure for the transfer of gases, so

P₂ - $P_{atm}$ = 3740 - 188 = 3552 Pa

This is the maximum pressure difference, where the person can still breathe,

Let's clear the height

h = 3552 / ρ g

h = 3552 / (1000 9.8)

h = 0.362 m

This is the maximum depth where the person can still breathe normally.

4 0

3 years ago

How can you show positive body languages with your mouth

sergey [27]

By just smiling. It normally makes you look more happy.And if your happy that's positive body languge

7 0

3 years ago

Three equal charge 1.8*10^-8 each are located at the corner of an equilateral triangle ABC side 10cm.calculate the electric pote

Arlecino [84]

Answer:

If all these three charges are positive with a magnitude of $1.8 \times 10^{-8}\; \rm C$ each, the electric potential at the midpoint of segment $\rm AB$ would be approximately $8.3 \times 10^{3}\; \rm V$ .

Explanation:

Convert the unit of the length of each side of this triangle to meters: $10\; \rm cm = 0.10\; \rm m$ .

Distance between the midpoint of $\rm AB$ and each of the three charges:

$d({\rm A}) = 0.050\; \rm m$ .
$d({\rm B}) = 0.050\; \rm m$ .
$d({\rm C}) = \sqrt{3} \times (0.050\; \rm m)$ .

Let $k$ denote Coulomb's constant ( $k \approx 8.99 \times 10^{9}\; \rm N \cdot m^{2} \cdot C^{-2}$ .)

Electric potential due to the charge at $\rm A$ : $\displaystyle \frac{k\, q}{d({\rm A})}$ .

Electric potential due to the charge at $\rm B$ : $\displaystyle \frac{k\, q}{d({\rm B})}$ .

Electric potential due to the charge at $\rm A$ : $\displaystyle \frac{k\, q}{d({\rm C})}$ .

While forces are vectors, electric potentials are scalars. When more than one electric fields are superposed over one another, the resultant electric potential at some point would be the scalar sum of the electric potential at that position due to each of these fields.

Hence, the electric field at the midpoint of $\rm AB$ due to all these three charges would be:

$\begin{aligned}& \frac{k\, q}{d({\rm A})} + \frac{k\, q}{d({\rm B})} + \frac{k\, q}{d({\rm C})} \\ &= k\, \left(\frac{q}{d({\rm A})} + \frac{q}{d({\rm B})} + \frac{q}{d({\rm C})}\right) \\ &\approx 8.99 \times 10^{9}\; \rm N \cdot m^{2} \cdot C^{-2} \\ & \quad \quad \times \left(\frac{1.8 \times 10^{-8} \; \rm C}{0.050\; \rm m} + \frac{1.8 \times 10^{-8} \; \rm C}{0.050\; \rm m} + \frac{1.8 \times 10^{-8} \; \rm C}{\sqrt{3} \times (0.050\; \rm m)}\right) \\ &\approx 8.3 \times 10^{3}\; \rm V\end{aligned}$ .

4 0

3 years ago

Describe how the kidney and bladder work together to remove waste from the body. (2 points)

san4es73 [151]

Answer:

The kidneys make urine by filtering wastes and extra water from blood. Urine travels from the kidneys through two thin tubes called ureters and fills the bladder. When the bladder is full, a person urinates through the urethra to eliminate the waste.

Explanation:

Good luckkk

8 0

3 years ago

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