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Nesterboy [21]
2 years ago
15

A student with a mass of 52 kg, starts from rest and travels down a 2 m slide. What is

Physics
1 answer:
Leya [2.2K]2 years ago
3 0

Answer:

https://www.ux1.eiu.edu/~cfadd/1350/Hmwk/Ch08/Ch8.html

Explanation:

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A force of 5 N is applied to the end of a lever that has a length
Klio2033 [76]

Answer:

The answer is 10Nm

Explanation: I ended up just messing around with the numbers, I multiplied 5 and 2 got 10 as my answer and it was right.

4 0
3 years ago
A small sphere has a harge of 9uC and other small sphere has a charge of 4uC.
Helga [31]

Answer:

Electrical force, F = 90 N

Explanation:

It is given that,

Charge on sphere 1, q_1=9\ \mu C=9\times 10^{-6}\ C

Charge on sphere 2, q_1=4\ \mu C=4\times 10^{-6}\ C

Distance between two spheres, d = 6 cm = 0.06 m

Let F is the electrical force between them. It is given by the formula of electric force which is directly proportional to the product of charges and inversely proportional to the square of distance between them such that,

F=k\dfrac{q_1q_2}{d^2}

F=9\times 10^9\times \dfrac{9\times 10^{-6}\times 4\times 10^{-6}}{(0.06)^2}

F = 90 N

So, the electrical force between them is 90 N. Hence, this is the required solution.

7 0
2 years ago
(i). A ball of mass 1.500 kg is attached to the end of a cord 1.50 m long. The ball moves in a horizontal circle. If the cord ca
Aleks04 [339]

(a) Let v be the maximum linear speed with which the ball can move in a circle without breaking the cord. Its centripetal/radial acceleration has magnitude

a_{\rm rad} = \dfrac{v^2}R

where R is the radius of the circle.

The tension in the cord is what makes the ball move in its plane. By Newton's second law, the maximum net force on it is

F = (1.500\,\mathrm{kg}) a_{\rm rad}

so that

(1.500\,\mathrm{kg}) \dfrac{v^2}{1.50\,\rm m} = 64.0\,\mathrm N

Solve for v :

v^2 = \dfrac{(64.0\,\mathrm N)(1.50\,\mathrm m)}{1.500\,\rm kg} \\\\ \implies \boxed{v = 8.00 \dfrac{\rm m}{\rm s}}

(b) The net force equation in part (a) leads us to the relation

F = \dfrac{mv^2}R \implies v = \sqrt{\dfrac{FR}m}

so that v is directly proportional to the square root of R. As the radius R increases, the maximum linear speed v will also increase, so the cord is less likely to break if we keep up the same speed.

6 0
1 year ago
what is the dot product and cross product of of two vectors if the angle is between them is 90 degree?​
DaniilM [7]

\sf{\pink{\underline{\underline{\blue{GIVEN:-}}}}}

  • The angle between the two vectors is 90° .

\sf{\pink{\underline{\underline{\blue{TO\: FIND:-}}}}}

  1. The dot product of two vectors .
  2. The cross product of two vectors .

\sf{\pink{\underline{\underline{\blue{SOLUTION:-}}}}}

⚡ Let \rm{\vec{a}} and \rm{\vec{b}} are the two vectors .

✍️ We have know that,

\orange\bigstar\:\rm{\pink{\boxed{\green{\vec{a}\:.\:\vec{b}\:=\:ab\cos{\theta}\:}}}}

Where,

  • θ = 90°

\rm{\implies\:\vec{a}\:.\:\vec{b}\:=\:ab\cos{90^{\degree}}\:}

  • cos 90° = <u>0</u>

\rm{\implies\:\vec{a}\:.\:\vec{b}\:=\:ab\times{0}\:}

\rm{\implies\:\vec{a}\:.\:\vec{b}\:=\:0\:}

\rm{\red{\therefore}} [1] The dot product of two vectors is “ <u>0</u> ” .

✍️ We have know that,

\orange\bigstar\:\rm{\pink{\boxed{\green{\vec{a}\:\times\:\vec{b}\:=\:ab\sin{\theta}\:}}}}

Where,

  • θ = 90°

\rm{\implies\:\vec{a}\:\times\:\vec{b}\:=\:ab\sin{90^{\degree}}\:}

  • sin 90° = <u>1</u>

\rm{\implies\:\vec{a}\:\times\:\vec{b}\:=\:ab\times{1}\:}

\rm{\implies\:\vec{a}\:\times\:\vec{b}\:=\:ab\:}

\rm{\red{\therefore}} [2] The cross product of two vectors is “ <u>ab</u> ” .

3 0
3 years ago
Read 2 more answers
Which of the following situations would cause the greatest decrease in the motion of molecules in a system?
Alina [70]

A. is the right answer since work is negative and Q which is heat in negative also

7 0
2 years ago
Read 2 more answers
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