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NISA [10]
3 years ago
11

What time of the day do you feel the most Energetic and what do you usually do in those moments?​

Physics
2 answers:
wlad13 [49]3 years ago
8 0
Night time i like to draw
iren2701 [21]3 years ago
4 0

Answer:

i typically feel the kost awake at night. i do my work (organize patinet info, label patient charts... etc.).

Explanation:

my circadian rythm is out of whack bc of dld

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An automobile starter motor has an equivalent resistance of 0.055 Ï and is supplied by a 12.0 v battery which has a 0.0305 Ï int
LiRa [457]
12 V is the f.e.m. \epsilon of the battery. The potential difference that is applied to the motor is actually the fem minus the voltage drop on the internal resistance r:
\epsilon - Ir
this is equal to the voltage drop on the resistance of the motor R:
RI
so we can write:
\epsilon - Ir = RI
and using r=0.0305~\Omega and R=0.055~\Omega we can find the current I:
I= \frac{\epsilon}{R+r}=140~A
8 0
3 years ago
Question in pic.. thanks!
11Alexandr11 [23.1K]

That's false. Displacement would be (r2 - r1) .

3 0
3 years ago
A measure of the average kinetic energy of the individual particles in an object is called
svlad2 [7]
<h2>Answer: Temperature </h2>

Temperature is a physical quantity that reflects the amount of heat in a body or medium. This amount of heat is related to the internal energy of a system (thermodynamically speaking), <u>according to the movement (speed) of each of the particles that compose it</u>, this means that it is related to its kinetic energy.

Therefore, the higher the kinetic energy, the higher the thermal energy in the system and the higher the temperature.

7 0
4 years ago
Nanotechnology is currently used in electronics for
VMariaS [17]

Answer:

data storage, OLEDS, and wires

Explanation:

3 0
3 years ago
A pendulum is constructed from a 6 kg mass attached to a strong cord of length 1.7 m also attached to a ceiling. Originally hang
valina [46]

Answer:

work done is -2.8  × 10⁻⁶ J

Explanation:

Given the data in the question;

mass of the pendulum m = 6 kg

Length of core = 1.7 m

Now, case1, mass is pulled aside a small distance of 7.6 cm and released from rest. so let θ₁ be the angle made by mass with vertical axis.

so, θ₁ = ( 7.6 × 10⁻² m / 1.7 m ) = 0.045 rad

In case2, mass is pulled aside a small distance of 8 cm and released from rest. so let θ₁ be the angle made by mass with vertical axis.

so, θ₂ = ( 8 × 10⁻² m / 1.7 m ) = 0.047 rad.

Now, the required work done will be;

W = \int\limits^{\theta_2} _{\theta_1} {r} \, d\theta

W = \int\limits^{\theta_2} _{\theta_1} {-mgl sin\theta } \, d\theta

W = -mgl  \int\limits^{0.047 } _{0.045 } {sin\theta } \, d\theta

W = -mgl[ -cosθ ]^{0.047}_{0.045 }

W = 6 × 9.8 × 1.7 × [ cos( 0.047 ) - cos( 0.045 ) ]

W = 6 × 9.8 × 1.7 × [ -2.8 × 10⁻⁸ ]

W = -2.8  × 10⁻⁶ J

Therefore, work done is -2.8  × 10⁻⁶ J

6 0
3 years ago
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