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nlexa [21]
1 year ago
9

Which type of radioactive decay has a positive charge?

Physics
1 answer:
Ostrovityanka [42]1 year ago
6 0

The type of radioactive decay that has a positive charge is alpha particles, which are positively charged.

<h3>What is radioactive decay?</h3>

The expression radioactive decay makes reference to the emission of ionizing radiation for a given atom, thereby an unstable atom may lose energy by releasing radiation.

Alpha particles are specific atomic particles consisting of 2 protons  (positive charge) and also 2 neutrons that share chemical bonds.

In conclusion, the type of radioactive decay that has a positive charge is alpha particles, which are positively charged.

Learn more about alpha particles here:

brainly.com/question/1621903

#SPJ1

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An electron in a television tube is accelerated uniformly from rest to a speed of 8.4\times 10^7~\text{m/s}8.4×10 ​7 ​​ m/s over
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Answer:

P=3.42×10^-6 J/s

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From the kinematics of motion with constant acceleration we know that :  

vf^2=vi^2+2*a(xf-xi)

Where :

• vf , vi, are the the final and the initial velocity of the electron  

• a is the acceleration of the electron  

• xf , xi are the final and the initial position of the electron .

Strategy for solving the problem : at first from the given information we calculate the acceleration of the electron.  

Givens: vf = 8.4 x 10^7 m/s , vi, = 0 m/s , xf = 0.025 m and xi = 0 m  

vf^2 =vi^2+2*a(xf-xi)

vf^2-vi^2=2*a(xf-xi)

2*a(xf-xi)= vf^2-vi^2

          a = (vf^2-vi^2)/2(xf-xi)

Pluging known information to get :

a = (vf^2-vi^2)/2(xf-xi)

  = 1.411 × 10^17

From the acceleration and the previous Eq. we can calculate the final velocity of the electron but a new position xf = 0.01 m  

so,

vf^2 =vi^2+2*a(xf-xi)

vf^2 =5.312× 10^7

From the following Eq. we can calculate the time elapsed in this motion .  

xf =xi+vi*t+1/2*a*t

xf =xi+vi*t+1/2*a*t

  t=√2(xf-xi)/a

 t=3.765×10^-10 s

now we can use the power P Eq.  

 P=W/Δt => ΔK/Δt  

Where: the work done W change the kinetic energy K of the electron ,

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P=1/2*m*vf^2-1/2*m*vi^2/Δt

P=3.42×10^-6 J/s

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