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4 years ago

How long have advances in astronomy been occurring? Only for the past few years

Physics

1 answer:

solniwko [45]4 years ago

3 0

I'd have to say that the list of choices doesn't go far enough.

Advances in Astronomy have been occurring for at least the past two millennia (2000 years). Maybe longer.

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An athlete has a final velocity of 9.5 m/s. If the athlete starts from the blocks and has an initial velocity of 0 m/s, what is

arlik [135]

Answer :

Explanation:
a =vf -vi/t
a = 9.5m/s -om/s/41 s
a = 0. 23 m/s²

4 0

3 years ago

The number of significant figures in the measurement 4.300×10^5 km are

ICE Princess25 [194]

Answer:

Explanation

Any numbers in scientific notation are considered significant. For example, 4.300 x 10-4 has 4 significant figures.

Answer From Gauth Math

8 0

3 years ago

What is a living organism? Give a few examples.

zhuklara [117]

Answer:

It's a individual form of life. Examples of this are bacterium , protists and fungus

7 0

3 years ago

Look at the Sankey diagram for a filament light bulb below. If the bulb is used in a desk lamp, what is the efficiency of the bu

guapka [62]

Answer:

The question does not state how the answer is to be entered. I would use 10% because that is most common.

Explanation:

You are using 300 J of energy to get 30 J of light energy. The fact that you can account for the left over energy is not relevant.

Efficiency = Work Out / Work In

Efficiency = 30 J / 300 J = 0.1

If you need this as a %, you can multiply by 100

Efficiency = 0.1 * 100 = 10%

6 0

2 years ago

Can someone solve this problem and explain to me how you got it

Zarrin [17]

1) The electric force changes by a factor of 25

2) The electric force changes by a factor of 16/9

Explanation:

The magnitude of the electrostatic force between two charges is given by Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where:

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_1, q_2$ are the two charges

r is the separation between the two charges

In this problem, let's call F the initial force between the two charges when they are at a distance of r.

Later, the distance is changed by a factor of 5. Let's assume it has been increased to a factor of 5: so the new distance is

r' = 5r

Therefore, the new force between the charges is:

$F' = k' \frac{q_1 q_2}{r'^2}=k' \frac{q_1 q_2}{(5r)^2}=\frac{1}{25}(k' \frac{q_1 q_2}{r'^2})=\frac{F}{25}$

So, the force has changed by a factor of 25.

The original force between the two charges is

$F=k\frac{q_1 q_2}{r^2}$

In this problem, we have:

- The distance between the charges is changed by a factor of 6:

r' = 6r

- The charges are both changed by a factor of 8:

$q_1' = 8q_1$

$q_2' = 8q_2$

Substituting into the equation, we find the new force:

$F' = k' \frac{q_1' q_2'}{r'^2}=k' \frac{(8q_1) (8q_2)}{(6r)^2}=\frac{64}{36}(k' \frac{q_1 q_2}{r'^2})=\frac{16}{9}F$

So, the force has changed by a factor of 16/9.

Learn more about electric force:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

6 0

3 years ago