Question

At 685 mmHg pressure and 50°C, a gas has a volume of 5.35 L. If the volume of the container decreases to 1.25 L, what is the amount of the pressure change?

Answer 1

2250mm Hg is the pressure change

Answer 2

Answer:

The amount of the pressure change is 2,246.8 mmHg.

Explanation:

In order to determine change in pressure we have to find the pressure of the gas when it occupied 1.25 L of volume.

So,to calculate the new pressure, we use the equation given by Boyle's law.

This law states that pressure is directly proportional to the volume of the gas at constant temperature.  

The equation given by this law is:

$P_1V_1=P_2V_2$ (at constant temperature)

where,

$P_1\text{ and }V_1$ are initial pressure and volume.

$P_2\text{ and }V_2$ are final pressure and volume.

We are given:

$P_1=685 mmHg\\V_1=5.35 L\\P_2=?\\V_2=1.25 L$

Putting values in above equation, we get:

$685 mmHg\times 5.35 L=P_2\times 1.25 L$

$P_2=\frac{685 mmHg\times 5.35 L}{1.25 L}=2931.8 mmHg$

The amount of the pressure change = $P_2-P_1$

$P_1-P_2=2931.8 mmHg-685 mmHg=2,246.8 mmHg$