20600Cal
Explanation:
Given parameters:
Mass of water = 319.5g
Initial temperature = 35.7°C
Final temperature = 100°C
Unknown:
Calories needed to heat the water = ?
Solution:
The calories is the amount of heat added to the water. This can be determined using;
H = m c Ф
c = specific heat capacity of water = 4.186J/g°C
H is the amount of heat
Ф is the change in temperature
H = m c (Ф₂ - Ф₁)
H = 319.5 x 4.186 x (100 - 35.7) = 85996.56J
Now;
1kilocalorie = 4184J
85996.56J to kCal;
= 20.6kCal = 20600Cal
learn more:
Specific heat brainly.com/question/3032746
#learnwithBrainly
Answer:
It would have to be around 9.8 volume
Explanation:
Answer:
v = 10 km/h
Explanation:
Step 1: Given data
- Distance traveled in the Bike Trip (d): 1 km
- Time elapsed in the Bike Trip (t): 0.1 h
Step 2: Calculate the speed in the Bike Trip
The speed (v) is equal to the distance traveled divided by the time elapsed. We will use the following mathematical expression.
v = d/t
v = 1 km/0.1 h
v = 10 km/h
The speed is 10 kilometers per hour.
Break down in to tiny prices as the water hit the tree