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2 years ago

13

Hydrogen reacts with an element to form a compound. which element would have the most valence electrons available to react with

hydrogen?

1 answer:

Alexus [3.1K]2 years ago

8 0

Answer:

the element is oxygen

Explanation:

it will react to give H2O

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Describe how a constant volume calorimeter can be used to measure the heat transferred from a burning piece of coal to cool wate

Vlad1618 [11]

Answer:

A Calorimeter is a device used to measure the amount of heat involved in a chemical or physical process.

Explanation:

Ex- when an exothermic reaction ( accompanied by or requiring absorption of heat)occurs in solution in a calorimeter, the heat produced by the reaction is absorbed by the solution increasing its temperature.

- When an endothermic reaction (Heat evolving reaction) occurs, the heat required is absorbed from the thermal energy of the solution, decreasing its temperature.

A burning piece of coal which is releasing heat due to its combustion and is transferred to water.

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7 0

3 years ago

In a single displacement reaction between sodium phosphate and barium, how much of each product (in grams) will be formed from 1

weeeeeb [17]

Answer:

A. 3.36g of Na.

B. 14.62g of Ba3(PO4)2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

3Ba + 2Na3PO4 → 6Na + Ba3(PO4)2

Next, we shall determine the mass of Ba that reacted and the mass of Na and Ba3(PO4)2 produced from the equation.

This is illustrated below:

Molar Mass of Ba = 137g/mol

Mass of Ba from the balanced equation = 3 x 137 = 411g

Molar mass of Na = 23g/mol

Mass of Na from the balanced equation = 6 x 23 = 138g

Molar mass of Ba3(PO4)2 = (3 x 137) + 2[31 + (4x16)] = 411 + 2[31 + 64] = 601g/mol

Mass of Ba3(PO4)2 from the balanced equation = 1 x 601 = 601g

Summary:

From the balanced equation above,

411g of Ba reacted to produce 138g of Na and 601g of Ba3(PO4)2.

A. Determination of the mass of Na produced by reacting 10g of Ba.

From the balanced equation above,

411g of Ba reacted to produce 138g of Na.

Therefore, 10g of Ba will react to produce = (10 x 138)/411 = 3.36g of Na.

Therefore, 3.36g of Na is produced.

B. Determination of the mass of Ba3(PO4)2 produced by reacting 10g of Ba.

From the balanced equation above,

411g of Ba reacted to produce 601g of Ba3(PO4)2.

Therefore, 10g of Ba will react to produce = (10 x 601)/411 = 14.62g of Ba3(PO4)2.

Therefore, 14.62g of Ba3(PO4)2 is produced.

7 0

3 years ago

When 2 grams of powdered lead (IV) oxide was added to 100 cm3 of hydrogen peroxide, water and oxygen were produced. Lead (IV) ox

kirza4 [7]

Answer:

The right answer is:

Replacing the powdered lead oxide with its large crystals

Removing lead (IV) oxide from the reaction mixture

Using 1.0 gram of lead (IV) oxide

Explanation:

Based on the given information this reaction is the catalytic decomposition of H₂O₂ into water and oxygen using Lead (IV) oxide as a catalyst.

The catalyst surface area is directly proportional to the reaction rate

So, Replacing the powdered lead oxide with its large crystals would decrease the reaction rate due to the has larger surface area than its large crystals.

2. Also, Removing lead (IV) oxide from the reaction mixture the reaction rate decreased because as the catalyst is removed.

3. Using 50 cm³ of hydrogen peroxide doesn't affect the rate because the concentration of the reactant doesn't change.

4. Using 1.0 gram of lead (IV) oxide would decrease the reaction rate because the amount of catalyst decreased

So, The right answer is:

Replacing the powdered lead oxide with its large crystals

Removing lead (IV) oxide from the reaction mixture

Using 1.0 gram of lead (IV) oxide

7 0

4 years ago

According to Combined Gas Law, which of the following is true? *

adelina 88 [10]

The second one, the third one, and the fourth one

3 0

4 years ago

Sodium phosphate dissolves as follows: na3po4(s) → 3na (aq) po4-(aq). How many moles of na3po4 are required to make 1. 0 l of so

bezimeni [28]

The 0.05 moles of $Na_{3}PO_{4}$ required to make 1 L of solution in which the $Na$ concentration is 0. 15 M.

Calculation,

The Sodium phosphate dissolves as follows:

$Na_{3}PO_{4}(s)$ → $3Na^{+} (aq)+PO_{4}^{-} (aq)$

To make 1. L of solution in which the $Na^{+$ concentration is 0. 15 M

The morality of $Na^{+$ = 0.15 M = number of moles / volume in lit

The morality of $Na^{+$ = 0.15 M = number of moles /1 Lit

number of moles of $Na^{+$ = 0.15 mole

The mole ratio is 1: 3

It means, the 1 mole of $Na_{3}PO_{4}(s)$ required to form 3 mole of $Na^{+$

So, to form 0.15 mole of $Na^{+$ = 1×0.15 / 3 moles of $Na_{3}PO_{4}(s)$ required.

Hence, number of moles of $Na_{3}PO_{4}(s)$ required = 0.05 moles.

learn about moles

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6 0

2 years ago