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PilotLPTM [1.2K]
3 years ago
5

What are the moles of gas are in a 30 liter scuba canister if the temperature of the canister is 300 K and the pressure is 200 a

tmospheres?
Chemistry
1 answer:
Lady_Fox [76]3 years ago
7 0

Answer:

n = 243.605

Explanation:

Given

Pressure, P = 200\ atm

Temperature, T = 300k

Volume, V = 30L

Required

Calculate the number of moles

We'll apply the following formula to solve this question

n = \frac{pV}{RT}

Where

R = 0.0821 L\ atm/(mol\ K)

The above equation is an illustration of the ideal gas law

Substitute values for p, V, R and T in:

n = \frac{pV}{RT}

n = \frac{200 * 30}{0.0821 * 300}

n = \frac{6000}{24.63}

n = 243.605

<em>Hence, there are 243.605 moles</em>

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A frying pan needs a Teflon coating of 1.00 mm in thickness to cover an area of 36.0 square inches. How many ounces of Teflon ar
Otrada [13]

Answer:

m = 0.659 ounce

Explanation:

It is given that,

The thickness of a Teflon coating is, d = 1 mm

Area of the coating, A = 36 inch²

The density of Teflon, d = 0.805 g/mL

We need to find ounces of Teflon are needed.

Firstly, find the volume of the Teflon needed,

1 inch² = 6.4516 cm²

36 inch² = 232.258 cm²

Density,

\rho=\dfrac{m}{V}

V is volume of the Teflon needed, V = Ad

So,

m=\rho V\\\\m=0.805\ g/cm^3\times 232.258\ cm^2 \times 0.1\ cm\\\\m=18.69\ g

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3 0
3 years ago
How many grams are there in 7.4 x 1023 molecules of H2SO4?
bazaltina [42]

7.4x10^23 = molecules of silver nitrate sample  

6.022x10^23 number of molecules per mole (Avogadro's number)  

Divide molecules of AgNO3 by # of molecules per mol  

7.4/6.022 = 1.229 mols AgNO3 (Sig Figs would put this at 1.3)  

(I leave off the x10^23 because they both will divide out)  

Use your periodic table to find the molar weight of silver nitrate.  

107.868(Ag) + 14(N) + 3(16[O]) = 169.868g/mol AgNO3  

Now multiply your moles of AgNO3 with your molar weight of AgNO3  

1.229mol x 169.868g/mol = 208.767g AgNO3

4 0
3 years ago
A 1.24g sample of a hydrocarbon, when completely burned in an excess of O2 yields 4.04g Co2 and 1.24g H20. Draw plausible struct
arsen [322]

Answer:

Plausible structure has been given below

Explanation:

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  • Number of mole = (mass/molar mass)

4.04 g of CO_{2} = \frac{4.04}{44}moles CO_{2} = 0.0918 moles of CO_{2}

1 mol of CO_{2} contains 1 mol of C atom

So, 0.0918 moles of CO_{2} contains 0.0918 moles of C atom

1.24 g of H_{2}O = \frac{1.24}{18}moles H_{2}O = 0.0689 moles of H_{2}O

1 mol of H_{2}O  contain 2 moles of H atom

So, 0.0689 moles of H_{2}O contain (2\times 0.0689)moles of H_{2}O or 0.138 moles of H_{2}O

Moles of C : moles of H = 0.0918 : 0.138 = 2 : 3

Empirical formula of hydrocarbon is C_{2}H_{3}

So, molecular formula of one of it's analog is C_{4}H_{6}

Plausible structure of C_{4}H_{6} has been given below.

4 0
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What part of an Atom undergoes change during radioactive decay
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It is clear that the core is subject to change
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Red light has a wavelength of about 7×10−7 m. will exposure to red light cause electrons to be emitted from cesium?
lorasvet [3.4K]
No i dont think so i checked in my book


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