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3 years ago

Dalila plans an experiment to examine plant growth. She

Physics

2 answers:

Harrizon [31]3 years ago

8 0

Answer:

Its A. On Edg

Explanation:

Hoochie [10]3 years ago

4 0

Answer:

The answer is: a column that shows how the dependent variable changes.

Explanation:

An experiment is a process that is carried out by a researcher in order to find out whether his hypothesis is valid. In order to conduct a proper experiment, it is very important to include both the "dependent" and "independent" variables.

A dependent variable refers to the variable that changes in response to the presence of an independent variable. On the contrary, an independent variable is the variable (such as factors) that is being changed in order to control the experiment.

Remember that independent variables do not depend on other factors. Thus, it is only the dependent variable's change that matters in an experiment.

This is the reason why Dalila needs to have a column that shows the dependent variable changes (and not the independent variable changes).

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For spring break you are traveling to San Diego. The trip is 1,746.4 miles and the trip takes 20.1 hours. How fast will you be t

postnew [5]

Answer:

86 mph

Explanation:

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2 years ago

Your Lead Teaching Assistant is initially seated on the top of a hemispherical ice mound of radius R = 30 m. Approximate the ice

saw5 [17]

Answer:

Height = 5.65 km

Explanation:

$3\pi r^2$ is the circumference or we can say measures the boundary of hemisphere of friction-less ice that he is sitting on.

So, the height will be = 2 x 3.14 x (30)^2 = 5654.7 m = 5.65 km

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3 years ago

Read 2 more answers

A mass m = 14 kg is pulled along a horizontal floor with NO friction for a distance d =5.7 m. Then the mass is pulled up an incl

frosja888 [35]

Answer:

W ≅ 292.97 J

Explanation:

1)What is the work done by tension before the block goes up the incline? (On the horizontal surface.)

Workdone by the tension before the block goes up the incline on the horizontal surface can be calculated using the expression;

W = (Fcosθ)d

Given that:

Tension of the force = 62 N

angle of incline θ = 34°

distance d =5.7 m.

Then;

W = 62 × cos(34) × 5.7

W = 353.4 cos(34)

W = 353.4 × 0.8290

W = 292.9686 J

W ≅ 292.97 J

Hence, the work done by tension before the block goes up the incline = 292.97 J

8 0

3 years ago

Starting from rest, a 2.1x10-4 kg flea springs straight upward. While the flea is pushing off from the ground, the ground exerts

nirvana33 [79]

Answer:

1.327363 m/s

0.00090243 m

Explanation:

u = Initial velocity

v = Final velocity

m = Mass of flea

Energy

$E=\frac{1}{2}m(v^2-u^2)\\\Rightarrow 3.7\times 10^{-4}=2.1\times 10^{-4}(v^2-0)\\\Rightarrow v=\sqrt{\frac{3.7\times 10^{-4}}{2.1\times 10^{-4}}}\\\Rightarrow v=1.32736\ m/s$

The velocity of the flea when leaving the ground is 1.327363 m/s

$W=F\times s\\\Rightarrow s=\frac{W}{F}\\\Rightarrow s=\frac{3.7\times 10^{-4}}{0.41}\\\Rightarrow s=0.00090243\ m$

The flea will travel 0.00090243 m upward

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3 years ago

How can you predict a child'a height?

Svet_ta [14]

A child height can be very tall or short

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3 years ago