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Kamila [148]
3 years ago
6

Dalila plans an experiment to examine plant growth. She

Physics
2 answers:
Harrizon [31]3 years ago
8 0

Answer:

Its A. On Edg

Explanation:

Hoochie [10]3 years ago
4 0

Answer:

The answer is: a column that shows how the dependent variable changes.

Explanation:

An experiment is <em>a process that is carried out by a researcher in order to find out whether his hypothesis is valid.</em> In order to conduct a proper experiment, it is very important to include both the <u>"dependent"</u> and <u>"independent" variables.</u>

A dependent variable refers to <u>the variable that changes in response to the presence of an independent variable.</u> On the contrary, an independent variable is <u>the variable (such as factors) that is being changed in order to control the experiment. </u>

Remember that<em> independent variables do not depend on other factors.</em> Thus, i<u>t is only the dependent variable's change that matters in an experiment.</u>

This is the reason why Dalila needs to have a column that shows the dependent variable changes (and not the independent variable changes).

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BB8 is an intergalactic robot (essentially a soccer ball with a half meter radius that can control how fast it rolls around) tha
hram777 [196]

Answer:

20 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

r = Radius of robot = 0.5 m

\alpha = Angular acceleration = 2 rad/s²

Linear acceleration is given by

a=r\alpha\\\Rightarrow a=0.5\times 2\\\Rightarrow a=1\ m/s^2

s=ut+\frac{1}{2}at^2\\\Rightarrow 50=0t+\frac{1}{2}\times 1\times t^2\\\Rightarrow t=\sqrt{\frac{50\times 2}{1}}\\\Rightarrow t=10\ s

While speeding up time taken is 10 seconds

v=u+at\\\Rightarrow v=0+1\times 10\\\Rightarrow v=10\ m/s

s=ut+\frac{1}{2}at^2\\\Rightarrow 50=10t-\frac{1}{2}\times 1\times t^2\\\Rightarrow t=\sqrt{\frac{50\times 2}{1}}\\\Rightarrow 50=10t-0.5t^2\\\Rightarrow -5t^2+100t-500=0

t=\dfrac{-100\pm \sqrt{100^2-4\left(-5\right)\left(-500\right)}}{2\left(-5\right)}\\\Rightarrow t=10\ s

The time taken to slow down is 10 seconds

Total time the trial is rum is 10+10 = 20 seconds

6 0
3 years ago
What is the weight, in pounds, of a 185-kg object on jupiter? express the weight numerically in pounds?
strojnjashka [21]

Befroe showing a numercial answer, It is necessary to clarify that pounds is not a unit of weight. Pounds is a unit of mass.


Mass is a property of matter which indicates the amount of matter (atoms of certain kind) that the object has. The mass of an object does not change whenever the object changes of environment. It is the same in water, on the air, on Jupiter, the Earth, Venus, the Moon. Any where.


On the other hand, weight is the product of mass times the acceleration of gravity. Therefore, weight is different from mass and it changes depending on the place.


To find the mass in pounds of a 185 kg object, you have to make a conversion of units.


The conversion factor is 1 kg = 2.2046 pounds ⇒ 1 = 2.2046 pounds / kg.


Therefore, 185 kg = 185 kg × 2.2046 pounds / kg = 407.851 pounds = 407.851 lb ← this is the mass in pounds.


To find the weight you had to search for the gravitational acceleration in Jupiter and calcuate it with the formula weight = mass × acceleration of gravity.


You find the value for acceleration of gravity in Jupiter  in internet as 24.79 m/s².


Weight = 185 kg × 24.79 /s² = 4,586 kg × m/ s² = 4,586 N.


There is a force unit in disuse called kiloponds. One kilopond equals 9.8 N. Hence, you can convert the weight 4,586 N to kiloponds in this way:


4,586 N × 1 kilopond / 9.8 N ≈ 468 kiloponds or 468,000 ponds ← weight

3 0
3 years ago
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