Answer:
Explanation:
We know that the tangent function relates the angle of the right triangle that forms the hot air balloon rising:
Differentiating (1) with respect to time, we get:
since x is a constant value. Replacing:
Answer:
Option B
Explanation:
According to quantum theory of radiation electromagnetic field or electromagnetic radiation( like light) produce by accelerated charge object and the quantum of EM radiations is photon which has discrete energy. So, EM field can have only certain values of total energy and no other value due the discrete nature of the energy of photon. Hence option B is correct
Answer:
V = 6.36 m³
Explanation:
For this exercise we will use fluid mechanics relations, starting with the continuity equation.
Let's write the flow equation
Q = v₁ A₁
The area of a circle is
A = π r²
Radius is half the diameter
A = π/4 d²
Q = v₁ π/4 d₁²
Q = π/ 4 15 0.03 2
Q = 0.0106 m3 / s
The volume of water in t = 10 min = 10 60 = 600 s
Q = V / t
V = Q t
V = 0.0106 600
V = 6.36 m³
Answer:
The speed of the raindrop and the mosquito is 8.02 m/s.
Explanation:
mass of mosquito = m
mass of drop = 45 m
initial velocity of mosquito, u = 0 m/s
initial velocity of drop, u' = 8.2 m/s
During the inelastic collision, the momentum of the system is conserved.
Let the speed of rain drop and the mosquito is v.
Use the conservation of momentum
m x u + 45 m x u' = (m + 45 m) v
m x 0 + 45 m x 8.2 = 46 m x v
v = 8.02 m/s
<span>Mass of the block m = 3.3kg
Angle of the slide = 30 degrees
Distance the block slides s = 2.10 m
Time taken to slide t = 1.6 s
Initially in rest condition so initial velocity u = 0.
We have an equation for distance s = (u x t) + (1/2) x (a t^2)
s = (0 x t) + (1/2) x (a x (1.6) ^2) => 2.10 = (1/2) x (a x2.56)
2.56a = 4.20 => a = 1.64
So the magnitude of the Acceleration a = 1.64 m/s^2</span>
