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Yanka [14]
3 years ago
12

Please help me out :)

Mathematics
1 answer:
Tomtit [17]3 years ago
5 0
(f+g)(x)=5x-6+x^2-4x-8
A.(f+g)(x)=x^2+x-14 is correct:)
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Paul makes 35% of his free throw shots. What decimal represents the amount of time he does not make his free throws​
lilavasa [31]

Answer:

65%

Step-by-step explanation:

because if he makes it 35 percent of the time out of 100%, he doesn’t make it 65% of the time. 100-35=65

6 0
3 years ago
Read 2 more answers
Write the equation using function notation f(x). then find f(0)<br><br> 2x^2 - 3y = 6
Grace [21]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: f(0) = -2

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \: 2 {x}^{2}  - 3y = 6

\qquad \tt \rightarrow \: 3y + 6 = 2 {x}^{2}

\qquad \tt \rightarrow \: 3y = 2 {x}^{2}  - 6

\qquad \tt \rightarrow \: y =  \cfrac{2 {x}^{2} - 6 }{3}

\qquad \tt \rightarrow \: y =  \cfrac{2 {}^{} }{3}  {x}^{2}  - 2

[ here, y can be replaced with f(x) because y is a function of x ]

\qquad \tt \rightarrow \: f(x) =  \cfrac{2 {}^{} }{3}  {x}^{2}  - 2

\large\textsf{Find f(0):}

\qquad \tt \rightarrow \: f(0) =  \cfrac{2 {}^{} }{3}  {(0)}^{2}  - 2

\qquad \tt \rightarrow \: f(0) =  0  - 2

\qquad \tt \rightarrow \: f(0) =   - 2

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

8 0
2 years ago
A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave
erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, L = 120 cm

Its wavelength \lambda_1 = 480 cm

                         \lambda_2 = 160 cm and \lambda_3 = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

  • The fundamental wavelength of a pipe which is open at both ends is 2L.
  • The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ 4L=4(120)=480\ cm

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒  \lambda_2=\frac{4L}{3}                                   ⇒  \lambda_3=\frac{4L}{5}

⇒ \lambda_2=\frac{4(120)}{3}                              ⇒  \lambda_3=\frac{4(120)}{5}

⇒ \lambda_2=\frac{480}{3}                                  ⇒  \lambda_3=\frac{480}{5}

⇒ \lambda_2=160\ cm                           ⇒   \lambda_3=96\ cm  

So the pipe is open at one end and closed at one end .

6 0
3 years ago
SOMEONE PLEASE HELP ME I DONT KNOW HOW TO DO THIS AT ALL
Lina20 [59]

Answer:

y=2cos(4\pi x)\\&#10;

Step-by-step explanation:

Since the amplitude of the cosine function is 2, I would put the multiply it by 2. There is no phase shift

The period is 1/2, so it would be 4pi

Plug them in into y=Acos(Bx), y=2cos(4pix)

6 0
2 years ago
7 divide by 28777 divided by 2877 equals what
mamaluj [8]
The answer is 8.45498149331, you can round it to the nearest thousandths place though, too.
8 0
3 years ago
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