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4 years ago

What happens to the force between two charges if one of the charges are doubled?

Physics

1 answer:

Julli [10]4 years ago

7 0

Answer:

The new force between the charges becomes double of the initial force.

Explanation:

The force acting between charge particles is given by :

$F=k\dfrac{q_1q_2}{r^2}$

k is electrostatic constant

r is distance between charges

If one of the charges are doubled, then, q₁ = 2q₁

The new force becomes,

$F'=\dfrac{2kq_1q_2}{r^2}\\\\F'=2F$

So, the new force between the charges becomes double of the initial force.

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When running a half marathon (13.1 miles), it took Kevin 8 minutes to run from mile marker 1 to mile marker 2, and 18 minutes to

Vsevolod [243]

Answer:

It took Kevin 26 minutes to run from markers 1 to 4

His average speed from mile markers 1 to 4 is 0.154 miles/minute

Kevin must run by average speed 0.1 miles/minute to finish the race

Explanation:

Lets explain how to solve the problem

A half marathon 13.1 miles

Kevin took 8 minutes to run from mile marker 1 to mile marker 2 and

18 minutes to run from mile marker 2 to mile marker 4

→ He took 8 minutes and 18 minutes to run from marker 1 to marker 4

→ The total time of the first 4 marker = 8 + 18 = 26 minutes

It took Kevin 26 minutes to run from markers 1 to 4

Average speed is total distance divided by total time

The average speed of Kevin as he ran from mile marker 1 to mile

marker 4 is the 4 miles divides by 26 minutes

→ Average speed = 4 ÷ 26 = $\frac{2}{13}$ = 0.154 miles/minute

His average speed from mile markers 1 to 4 is 0.154 miles/minute

It took Kevin 71 minutes to pass mile marker 9

Kevin need to complete the race in 112 minutes, then what must

Kevin's average speed be as he travels from mile marker 9 to the

finish line?

The total distance of the race is 13.1 miles, he ran 9 miles

→ The remaining distance = 13.1 - 9 = 4.1 miles

He must run 4.1 miles to complete the race

The total time is 112 minutes, he used 71 minutes to run the first 9 miles

→ The remaining time = 112 - 71 = 41 minutes

He must finish the 4.1 miles in 41 minutes

→ His average speed for the last part of the race = 4.1 ÷ 41 = 0.1 mi/min

Kevin must run by average speed 0.1 miles/minute to finish the race

7 0

3 years ago

Read 2 more answers

And are facing each other of the two and the friend are on the separate more you when the moving. Your friend weighs a lot on yo

puteri [66]

Buddy, I think you need to evaluate your question and fix it. Because it's not making any sense, whatsoever.

7 0

3 years ago

A 565 N rightward force pulls a large box across the floor with a constant velocity of 0.75 m/s. If the coefficient of friction

alukav5142 [94]

The first thing you should know is that the friction force is equal to the coefficient of friction due to normal force.
Therefore, clearing the normal force we have:
The friction is 565N.
(565 / 0.8) = 706.25N. weight.

6 0

4 years ago

What is the energy of a mole of photons that have a wavelength of 413 nm? (h = 6.626 × 10⁻³⁴ J • s and c = 3.00 × 10⁸ m/s)

Triss [41]

Answer:

Energy of one mole of photon will be $2.89\times 10^5J$

Explanation:

We have given wavelength of photon $\lambda =413nm=413\times 10^{-9}m$

Velocity of light is given $c=3\times 10^8m/sec$

Plank's constant $h=6.626\times 10^{-34}Js$

Energy of the photon is given by $E=\frac{hc}{\lambda }=\frac{6.626\times 10^{-34}\times 3\times 10^8}{413\times 10^{-9}}=0.048\times 10^{-17}J$

We have to find the energy of one mole of photon

One mole of photon is equal to $6.023\times 10^{23}photon$

So energy of one mole of photon will be equal to $6.023\times 10^{23}\times 0.048\times 10^{-17}=2.89\times 10^5J$

So energy of one mole of photon will be $2.89\times 10^5J$

6 0

3 years ago

Which resistor dissipates the most power, the one with the greatest resistance or the one with the least resistance? explain why

Klio2033 [76]

The power dissipated by a resistor is equal to
$P=R I^2$
where R is the value of the resistance and I is the current flowing through the resistor. From the formula, we can see that the larger R, the larger the dissipated power, so the greatest resistance dissipates more power.

5 0

3 years ago