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Vikentia [17]
2 years ago
14

Air contained in a rigid, insulated tank fitted with a paddle wheel, initially at 300 K, 2 bar, and a volume of 2 m3, is stirred

until its temperature is 500 K. Assuming the ideal gas model, for the air, and ignoring kinetic and potential energy, determine
Physics
1 answer:
aalyn [17]2 years ago
3 0

Answer:

The final pressure in bar will be "\frac{10}{3} \ Bar".

Explanation:

As we know,

PV = nRT

\frac{P_1}{T_1} =\frac{P_2}{T_2} =CONST

then,

⇒ \frac{2 \ bar}{300 \ K} = \frac{P_2}{500 \ K}

⇒ P_2=(\frac{2}{300}\times 500 )Bar

        =\frac{10}{3} \ Bar

Thus the above is the correct answer.

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Why is there a universe at all
Soloha48 [4]

Answer:GOD ;)

Explanation:

6 0
2 years ago
Consider the following equilibrium at 979 K for the dissociation of molecular iodine into atoms of iodine. I2(g) equilibrium rea
GenaCL600 [577]

Answer:  I_2=  0.0050 M

I = 0.0155 M

Explanation:

Initial moles of  I_2 = 0.072 mole

Volume of container = 3.9 L

Initial concentration of I_2=\frac{moles}{volume}=\frac{0.072moles}{3.9L}=0.018M  

The given balanced equilibrium reaction is,

                 I_2(g)\rightleftharpoons 2I(g)

Initial conc.         0.018 M            0

At eqm. conc.    (0.018-x) M      (2x) M  

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[I]^2}{[I_2]}

K_c=\frac{(2x)^2}{0.2-x}

we are given :  K_c=1.60\times 10^{-3}

Now put all the given values in this expression, we get :

1.60\times 10^{-3}=\frac{(2x)^2}{(0.018-x)}

x=0.0025

So, the concentrations for the components at equilibrium are:

[I]=2\times x=2\times 0.0025=0.0050

[I_2]=0.018-x=0.018-0.0025=0.0155

Hence, concentrations of I_2 and I are 0.0050 M ad 0.0155 M respectively.

4 0
3 years ago
the force that gravitation exerts upon a body, equal to the mass of the body times the local acceleration of gravity
PIT_PIT [208]

The force that gravitation exerts upon a body, equal to the mass of the body times the local acceleration of gravity is known as weight.

Weight is the force of gravity acting on a body.

The formula is :

                                W =mg

Here,

W is the weight or force acting on the body. m is the mass of the body, and g is the gravitational acceleration.

Since weight is also a force, so its SI unit is also newton. The value of weight varies from place to place depending on the gravity. Its value can also be equal to zero.

If you need to learn about the difference between mass and weight, click here

brainly.com/question/23876249?referrer=searchResults

#SPJ4

8 0
1 year ago
A certain string can withstand a maximum tension of 39. N without breaking. A child ties a 0.43 kg stone to one end and, holding
frez [133]

Answer:

Bottom of the circle.

Explanation:

At the top of the circle the tension and the weight contribute on being the centripetal force, at the middle of the circle only the tension contributes on being the centripetal force (the weight being perpendicular to it), while <u>at the bottom</u> of the circle the tension contributes on being the centripetal force (as always) <em>but the weight against to it</em>, so here is where the tension must be greater to allow the same centripetal force as the other cases, thus here is where the string will break.

6 0
3 years ago
If a train is going 60 m/s hits the brakes, and it takes the train 1 minute 25 seconds to stop, what is the train’s acceleration
Cloud [144]
Hey there, the answer is ..............................  About 0.7 m/sec^2
<span>
Acceleration is the change in speed / time </span>

<span>Change in speed is 60 m/sec </span>

<span>Time is 1 minute 25 second. Convert that to seconds. </span>

<span>Divide the change in speed by the time in seconds.

About 0.7 m/sec^2

 </span><span>So the acceleration is - 60 / 85 = - 0.71 m/s^2 

HOPE I HELPED!!!!!!!!!!
</span>
8 0
3 years ago
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