Answer:
The young tree, originally bent, has been brought into the vertical position by adjusting the three guy-wire tensions to AB = 7 lb, AC = 8 lb, and AD = 10 lb. Determine the force and moment reactions at the trunk base point O. Neglect the weight of the tree.
C and D are 3.1' from the y axis B and C are 5.4' away from the x axis and A has a height of 5.2'
Explanation:
See attached picture.
Answer:
The direct current that will produce the same amount of thermal energy is 1.83 A
Explanation:
Given;
maximum current, I₀ = 2.59 A
The average power dissipated in a resistor connected in an AC source is given as;
Where;
The average power dissipated in a resistor connected in a DC source is given as;
where;
is direct current
Solve equation (1) and (2) together;
Therefore, the direct current that will produce the same amount of thermal energy is 1.83 A
Answer:
B) The ratio of the speed of sound in rod A to the speed of sound in rod B is 1.
Explanation:
Applying Hooke's law,
F = -kx
Where,
F = force
k = spring stiffness
x = length
Element A
F/7k = x
Since, mass = F/A
Ma = 7Mb
Therefore,
7Mb/A*7kb = x
Mb/A*k = x
Element B
F/k = x
Since, mass = F/A
Mb = Mb
Therefore,
Mb/A*kb = x
Ratio of mass of element A and element B
Mb/A*kb : Mb/A*kb
1 : 1
Answer:
Explanation:
Potential energy is the energy stored within an object, due to the object's position, arrangement or state
Answer:
The coefficient of friction in the hall is 0.038
Explanation:
Given;
mass of the Parker, m = 73.2 kg
applied force on the parker, F = 123 N
frictional force, Fs = 27.4 N
the coefficient of friction in the hall = ?
frictional force is given by;
Fs = μN
Where;
μ is the coefficient of friction
N is normal reaction = mg
Fs = μmg
μ = Fs / mg
μ = (27.4) / (73.2 x 9.8)
μ = 0.038
Therefore, the coefficient of friction in the hall is 0.038