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Kisachek [45]
3 years ago
10

Air pollution affects everyone equally. True or false

Physics
2 answers:
ra1l [238]3 years ago
8 0
Overcourse this is true.

Air pollution causes distortions to the air organisms breathe.
The type of pollution that is caused by particles in the air is called Particulates and it is a type of air pollution.These are highly deadly for all living beings. The minute solid or liquid particles that are present in the air or atmosphere can cause a great amount of damage to the lungs of humans. WHO or World Health Organization has designated Particulates as Group 1 carcinogen. The particulates are considered as the deadliest form of air pollution as it can mix with blood unhindered and create death, heart attack or heart ailment and even go as far as creating DNA mutation. 

prohojiy [21]3 years ago
7 0
False. bc those with asthma are affect more than others. 
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If the coefficient of friction is 0.65, what frictional force would be on a 2N object?
castortr0y [4]

Answer:

0

Explanation:

F=u*N

There is no force pushing the object which results in 0 friction

7 0
3 years ago
Please help An object is observed to move under the following equation of motion ... x(t) = A√t ... take A =√2. Determine the eq
tatuchka [14]

Explanation:

Function of distance w.r.t time :

x(t) = \: y =   \sqrt{2t}

Differentiate w.r.t time to get velocity :

\frac{dy}{dt}  = v =  \frac{1}{ \sqrt{2t} }

Differentiate w.r.t time to get Acceleration :

\frac{d^2y}{dx^2}  = a \:  =  -  \frac{1}{2t \sqrt{2t} }

3 0
4 years ago
A 100 Ω resistor is connected in series with a 47 µF capacitor and a source whose maximum voltage is 5 V, operating at 100.0 Hz.
Pani-rosa [81]

Answer:

X_c=-33.86275385\Omega

|Z|=105.5778675\Omega

I=0.04735841062A

\phi=20.78612878\°

Explanation:

The electrical reactance is defined as:

X_c=-\frac{1}{2\pi fC}

Where:

f=Frequency\\C=Capacitance

So, replacing the data provided by the problem:

X_c=\frac{1}{2\pi *100*(47*10^{-6} )} =-33.86275385\Omega

Now, the impedance can be calculated as:

Z=R+jX_c

Where:

R=Resistance\\X_c= Capacitive\hspace{3}reactance

Replacing the data:

Z=100-j33.86275385

In order to find the magnitude of the impedance we can use the next equation:

|Z|=\sqrt{(R^2)+(X_c^2)}=\sqrt{(100)^2+(-33.86275385)^2} =105.5778675\Omega

We can use Ohm's law to find the current:

V=I*Z\\I=\frac{V}{Z}

Therefore the current is:

I=\frac{5}{100-j33.86275385}=0.04485638113+0.01518960593j

And its magnitude is:

|I|=\sqrt{(0.04485638113)^2+(0.01518960593)^2} =0.04735841062\Omega

Finally the phase angle of the current is given by:

\phi=arctan(\frac{0.01518960593}{0.04485638113})=20.78612878\°

5 0
3 years ago
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Kaylis [27]

Answer:

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Explanation:

Ano yung sa inyo???

7 0
3 years ago
You are handed a 5.00kg • 10^-3 coin and gold that it is gold.
OLga [1]
Nkkhgg chu toookooydddgnbjkoo
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