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almond37 [142]
2 years ago
10

State the law of conservation of linear momentum using Newton's third law of deduce this ​

Physics
1 answer:
MArishka [77]2 years ago
7 0

Answer:

Derivation of Conservation of Momentum

Applying Newton's third law, these two impulsive forces are equal and opposite i.e. is equal to the change in momentum of the first object. is equal to the change in momentum of the second object. This relation suggests that momentum is conserved during the collision.

Explanation:

Hope it helps!!!

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Antrenmanlarla matematik 17.gün cevaplari acil​
Ray Of Light [21]

Answer:

ne diyorsun anlamadım cevap anhtarımı

7 0
3 years ago
A cat stalks an unsuspecting mouse. The movement of the cat is shown in the following graph of the horizontal position, x, again
stellarik [79]

Answer:

0.25 m/s

Explanation:

Average velocity = change in displacement / change in time

v = (1.5 m − 2.5 m) / (6 s − 2 s)

v = -0.25 m/s

The average speed is 0.25 m/s.

3 0
3 years ago
A hydrogen atom consists of a proton and an electron. If the orbital radius of the electron increases
tamaranim1 [39]

Answer:

The potential energy increases  if the orbital radius increases.

Explanation:

  The orbital radius of the electron increases means the distance from the nucleus of the hydrogen atom increase.

 The nucleus is positively charged .

The potential energy is given by  P.E = -\frac{Ze^{2} }{r}

             where Z is the atomic number      

                           r is the radius

The negative sign indicates that the electron which is revolving is bound to nucleus.

As the radius and potential energy are inversely proportional it is clear that when <em>radius increase</em> the<em> potential energy become less negative </em>which means the potential energy increases when the orbital radius increase.

5 0
3 years ago
A 3-kg ball is thrown with a speed of 8 m/s at an unknown angle above the horizontal. The ball attains a maximum height of 2.8 m
Alina [70]

Answer:

13.5 J

Explanation:

mass of ball, m = 3 kg

maximum height, h = 2.8 m

initial speed, u = 8 m/ s

Angle of projection, θ

use the formula of maximum height

H = \frac{u^{2}Sin^{2}\theta }{2g}

2.8 = \frac{8^{2}Sin^{2}\theta }{2\times 9.8}

Sin θ = 0.926

θ = 67.8°

The velocity at maximum height is u Cosθ = 8 Cos 67.8 = 3 m/s

So, kinetic energy at maximum height

K=\frac{1}{2}mv^{2}

K = 0.5 x 3 x 3 x 3

K = 13.5 J

8 0
3 years ago
Step 3 - Fillin the missing numbers:<br> 21 -3 -10 24<br> b d
mash [69]

Answer:

b = 2

c = -1

d = -2

Explanation:

Got this question right on edge

4 0
3 years ago
Read 2 more answers
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