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Mars2501 [29]
4 years ago
7

Find density of nitrogen dioxide at 75*C and 0.805 atm.

Chemistry
1 answer:
Eva8 [605]4 years ago
5 0

Answer:

1 (348) (D2) = 273 (2.05) (0.805) D2= 1.29 g/L

Explanation:

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Which of the following is the correct measurement for the volume of liquid shown below?
mr Goodwill [35]

Answer:

A. 3.5ml

Explanation:

lowest point of liquid or meniscus

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3 years ago
what is the maximum number of covalent bonds that an oxygen atom with atomic number 8 can make with hydrogen? question 4 options
Oliga [24]

Maximum number of covalent bonds that an oxygen atom can make with hydrogen is 2.

  • the ground state electronic configuration of oxygen is 2s² 2p⁴ that means it has 6 electrons in its valence shell and require two electrons are required to complete its octate.
  • Two bonds are created when an electron donor atom shares the two needed electrons with oxygen. The ability of two oxygen atoms to share valence electrons results in the creation of a double bond between the two atoms.
  • There are no longer any empty orbitals in the octet of oxygen after it is complete. As a result, it is unable to accept more electrons or create more bonds.

Therefore, Oxygen can only generate two bonds because it needs two additional electrons to complete its octet, after which it will run out of empty orbitals in which to receive additional electrons and create additional bonds.

learn more about octate here:

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3 0
1 year ago
For which of the following is heat energy absorbed?
Dvinal [7]
Your answer is sublimation.

8 0
3 years ago
Read 2 more answers
Calculate the concentration of the following solution in mol/dm3 0.1 moles of NaCl in 200 cm3
taurus [48]
1 cm ^{3} = 0.001 dm ^{3}. Therefore 200 cm ^{3} = 0.2 dm ^{3}. Molarity = \frac{number of moles of NaCl}{volume of the solution} =  \frac{0.1}{0.2} = 0.5 mol/dm^{3}. Hope this helps.
8 0
3 years ago
Determine the pH of a 0.048 M hypochlorous acid (HClO) solution. Hypochlorous acid is a weak acid (Ka = 4.0 ✕ 10−8 M).
storchak [24]

pH of 0.048 M HClO is 4.35.

<u>Explanation:</u>

HClO is a weak acid and it is dissociated as,

HClO ⇄ H⁺ + ClO⁻

We can write the equilibrium expression as,

Ka = $\frac{[H^{+}] [ClO^{-}]  }{[HClO]}

Ka = 4.0 × 10⁻⁸ M

4.0 × 10⁻⁸ M = $\frac{x \times x }{0.048}

Now we can find x by rewriting the equation as,

x² =  4.0 × 10⁻⁸ × 0.048

   = 1.92 × 10⁻⁹

Taking sqrt on both sides, we will get,

x = [H⁺] = 4.38 × 10⁻⁵

pH = -log₁₀[H⁺]

     = - log₁₀[ 4.38 × 10⁻⁵]

   = 4.35

8 0
3 years ago
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