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Mars2501 [29]
3 years ago
7

Find density of nitrogen dioxide at 75*C and 0.805 atm.

Chemistry
1 answer:
Eva8 [605]3 years ago
5 0

Answer:

1 (348) (D2) = 273 (2.05) (0.805) D2= 1.29 g/L

Explanation:

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3 years ago
5. A 5.00 g sample of an unknown substance was heated from 25.2 C to 55.1 degrees * C , and it required 133 to do so. Identify t
Leviafan [203]

Answer:

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Explanation:

Given

T_1 = 25.2^oC

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\triangle Q= 133J

<em>See attachment for chart</em>

Required

Identify the unknown substance

To do this, we simply calculate the specific heat capacity from the given parameters using:

c = \frac{\triangle Q}{m\triangle T}

This gives:

c = \frac{\triangle Q}{m(T_2 - T_1)}

So, we have:

c = \frac{133J}{5.00g * (55.1C - 25.2C)}

c = \frac{133J}{5.00g * 29.9C}

c = \frac{133J}{149.5gC}

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From the attached chart, we have:

Al(s) = 0.89\ J/gC --- The specific heat capacity of Aluminum

<em>Hence, the unknown substance is Aluminum</em>

7 0
3 years ago
Based on the kinetic molecular theory (KMT), which statement is true?
nataly862011 [7]

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Answer:

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