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3 years ago

A block of aluminum occupies a volume of 0.015 L and has a mass of 40.5 g. What is its density

Chemistry

1 answer:

yan [13]3 years ago

7 0

Answer:

<h2>Density = 2700 g/L</h2>

Explanation:

Density of a substance can be found by using the formula

$Density = \frac{mass}{volume}$

From the question

volume = 0.015 L

mass = 40.5 g

Substitute the values into the above formula and solve for the Density

That's

$Density = \frac{40.5}{0.015}$

We have the final answer as

Density = 2700 g/L

Hope this helps you

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What is the volume if 1.5 mol of gas has a pressure of 700 torr at 15°C?

Tasya [4]

Answer:

V = 38.48 L

Explanation:

Given that,

No. of moles = 1.5 mol

Pressure, P = 700 torr

Temperature, T = 15°C = 288 K

We need to find the volume of the gas. The ideal gas equation is given by :

$PV=nRT\\\\V=\dfrac{nRT}{P}\\\\V=\dfrac{1.5\times 62.36\times 288}{700}\\\\V=38.48\ L$ , R = L.Torr.K⁻¹.mol⁻¹

So, the required volume is equal to 38.48 L.

7 0

3 years ago

For the reaction of hydrogen with iodine

fenix001 [56]

Answer:

$r_{H_2} = \frac{-1}{2} r_{HI}$

Explanation:

Hello!

In this case, considering the given chemical reaction:

$H_2(g) + I_2(g) \rightarrow 2HI(g)$

Thus, by applying the law of rate proportions, we can write:

$\frac{1}{-1} r_{H_2} = \frac{1}{-1}r_{i_2} = \frac{1}{2} r_{HI}$

Whereas the stoichiometric coefficients of reactants are negative due their disappearance and that of the product is positive due to its appearance. In such a way, when we relate the rate of disappearance of hydrogen gas to the rate of formation of hydrogen iodide, we obtain:

$r_{H_2} = \frac{-1}{2} r_{HI}$

Best regards!

8 0

2 years ago

In a lab experiment 80.0 g of ammonia [NH3] and 120 g of oxygen are placed in a reaction vessel. At the end of the reaction 72.2

valentinak56 [21]

The percent yield of the reaction : 89.14%

<h3>Further explanation</h3>

Reaction of Ammonia and Oxygen in a lab :

mass NH₃ = 80 g

mol NH₃ (MW=17 g/mol):

$\dfrac{80}{17}=4.706$