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4 years ago

Determine the number of protons, electrons, and neutrons for cobalt with a charge of +6 and a mass of 61.

Chemistry

1 answer:

romanna [79]4 years ago

8 0

Protons-27
Electrons-21
Neutrons-32 (According to google), but 34 according to your set of numbers.

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When a 7.00 g7.00 g sample of KBrKBr is dissolved in water in a calorimeter that has a total heat capacity of 2.72 kJ⋅K−1,2.72 k

algol13

Answer : The molar heat of solution of KBr is 19.9 kJ/mol

Explanation :

Mass of KBr = 7.00 g

Molar mass of KBr = 119 g/mole

Heat capacity = 2.72 kJ/K

Change in temperature = 0.430 K

First we have to calculate the moles of KBr.

$\text{ Moles of }KBr=\frac{\text{ Mass of }KBr}{\text{ Molar mass of }KBr}=\frac{7.00g}{119g/mole}=0.0588moles$

Now we have to calculate the heat of the reaction.

$q=c\times \Delta T$

where,

q = amount of heat = ?

$c$ = heat capacity = $2.72kJ/K$

$\Delta T$ = change in temperature = 0.430 K

Now put all the given values in the above formula, we get:

$q=2.72kJ/K\times 0.430K$

$q=1.17kJ$

Now we have to calculate the molar heat of solution of KBr.

$\text{Molar heat of solution of }KBr=\frac{q}{n}$

where,

n = number of moles of KBr

$\text{Molar heat of solution of }KBr=\frac{1.17kJ}{0.0588moles}=19.9kJ/mol$

Therefore, the molar heat of solution of KBr is 19.9 kJ/mol

4 0

4 years ago

What is metallic conductivity ?

melamori03 [73]

Explanation:

metallic conduction:the movement of electrons through a metal, with no changes in the metal and no movement of the metal atoms.

I hope this help uuhh............

6 0

2 years ago

4NH3 + 502 --> 4NO + 6H20

gregori [183]

Answer:

5.52 g

Explanation:

4NH₃ + 5O₂ → 4NO + 6H₂O

First we convert the given masses of both reactants into moles, using their respective molar masses:

6.30 g NH₃ ÷ 17 g/mol = 0.370 mol NH₃

1.80 g O₂ ÷ 32 g/mol = 0.056 mol O₂

Now we calculate with how many NH₃ moles would 0.056 O₂ moles react, using the stoichiometric coefficients:

0.056 mol O₂ * $\frac{4molNH_3}{5molO_2}$ = 0.045 mol NH₃

As there more NH₃ moles than required, NH₃ is the excess reactant.

Then we calculate how many NH₃ moles remained without reacting:

0.370 mol NH₃ - 0.045 mol NH₃ = 0.325 mol NH₃

Finally we convert NH₃ moles into grams:

0.325 mol NH₃ * 17 g/mol = 5.52 g

7 0

3 years ago

Which of the following involves a chemical change?

Liula [17]

Answer:

Explanation:

hehe plss give me a heart

7 0

3 years ago

Read 2 more answers

Various members of a class of compounds, alkenes, react with hydrogen to produce a corresponding alkane. Termed hydrogenation, t

Vitek1552 [10]

Answer: The mass of decane produced is $1.743\times 10^2g$

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

Mass of hydrogen gas = 2.45 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1:, we get:

$\text{Moles of }H_2=\frac{2.45g}{2g/mol}=1.225mol$

The chemical equation for the hydrogenation of decene follows:

$C_{10}H_{20}(l)+H_2(g)\rightarrow C_{10}H_{22}(s)$

As, decene is present in excess. So, it is considered as an excess reagent.

Thus, hydrogen gas is a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

1 mole of hydrogen gas produces 1 mole of decane.

So, 1.225 moles of hydrogen gas will produce = $\frac{1}{1}\times 1.225=1.225mol$ of decane

Now, calculating the mass of decane by using equation 1, we get:

Moles of decane = 1.225 mol

Molar mass of decane = 142.30 g/mol

Putting values in equation 1, we get:

$1.225mol=\frac{\text{Mass of decane}}{142.30g/mol}\\\\\text{Mass of carbon dioxide}=(1.225mol\times 142.30g/mol)=174.3g=1.743\times 10^2g$

Hence, the mass of decane produced is $1.743\times 10^2g$

5 0

3 years ago