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Alexxandr [17]
3 years ago
14

The weld bead in SMAW is formed by the?

Physics
1 answer:
SVETLANKA909090 [29]3 years ago
7 0
The answer is C I just took this quiz.
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A 215-kg load is hung on a wire of length of 3.60 m, cross-sectional area 2.00 10-5 m2, and Young's modulus 8.00 1010 N/m2. What
Y_Kistochka [10]

Answer:

4.74 * 10^-3

Explanation:

6 0
3 years ago
What is the purpose of nucleophilic substitution reactions of akyly halides experiment?
OleMash [197]

The purpose of nucleophilic substitution reactions of alkyl halides experiment is to demonstrate in the laboratory setting Nucleophilic substitution reactions of alkyl halides.

In this it is been  aimed to observe nucleophilic substitution reactions, SN1 and SN2 will by the addition of a solvent to mixtures of alkyl halides. In order to make this experiment effective a standard procedure is being used  and noted observations while each reaction occurred.

Nucleophilic substitution reactions are an important class of reactions that allow the interconversion of functional groups. For alcohols, the range of substitution reactions possible can be increased by utilizing the tosylates (R-OTs), an alternative method of converting the -OH to a better leaving group.

To learn more about nucleophilic substitution reactions

brainly.com/question/7022020?referrer=searchResults

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7 0
2 years ago
How is a scientific theory different from a hypothesis?
Maslowich
A scientific theory is different from a hypothesis because a theory is a educated guess that is being worked on and proven correct and a hypothesis is a educated guess it is a guess that needs to be proven.
7 0
4 years ago
What is the slit spacing of a diffraction necessary for a 600 nm light to have a first order principal maximum at 25.0°?
Sauron [17]

Explanation:

Given that,

Wavelength of light, \lambda=600\ nm=6\times 10^{-7}\ m

Angle, \theta=25^{\circ}

We need to find the slit spacing for diffraction. For a diffraction, the first order principal maximum is given by :

d\sin\theta=n\lambda

n is 1 here

d is slit spacing

d=\dfrac{\lambda}{\sin\theta}\\\\d=\dfrac{6\times 10^{-7}}{\sin(25)}\\\\d=1.41\times 10^{-6}\ m\\\\d=1.41\ \mu m

So, the slit spacing is 1.41\ \mu m.

6 0
4 years ago
Two loudspeakers emit sound waves along the x-axis. A listener in front of both speakers hears a maximum sound intensity when sp
grandymaker [24]

Answer:

frequency of the sound = f = 1,030.3 Hz

phase difference = Φ = 229.09°

Explanation:

Step 1: Given data:

Xini = 0.540m

Xfin = 0.870m

v = 340m/s

Step 2: frequency of the sound (f)

f = v / λ

λ = Xfin - Xini = 0.870 - 0.540 = 0.33

f = 340 / 0.33

f = 1,030.3 Hz

Step 3: phase difference

phase difference = Φ

Φ = (2π/λ)*(Xini - λ) = (2π/0.33)* (0.540-0.33) = 19.04*0.21 = 3.9984

Φ = 3.9984 rad * (360°/2π rad)

Φ = 229.09°

Hope this helps!

5 0
3 years ago
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