Answer:
Lipid A, present as part of a Lipopolysaccharide complex in the outer membrane of gram negative bacteria cell walls, should be the answer, but it does not appear in the options included. As option C states “Amino terminal triglyceride”, and triglycerides are lipids, then we could explore this option. However, nothing is said about lipoproteins linked to Lipid A (that acts as an endotoxin) to mention carboxyl- or amino- terminals (options A and C), so I would consider the core oligosaccharide option as more probable (see below*).
Explanation:
Murein and peptidoglycan are names used to refer bacterial cell walls main component. This complex is mainly composed by disaccharide units composed of alterning N-acetyl-muramic acid (that contains the same structure of N-acetylglucosamine, plus a tetrapeptide) and N-acetyl-glucosamine, which form the backbone of the wall. These are responsible for the strength and shape of the cell. In Gram negative bacteria, an outer layer called outer membrane, as it contains an important amount of lipids, linked to other molecules, is also present. There, Lipid A is associated to a core oligosaccharide, and subsequently to the Antigen O (polysaccharide) forming Liposaccharides, wich stabilize and give strength to gram negative cell walls.
*Lipid A is the main responsible molecule for toxicity in these cell walls. As in question answer options, is included in B option “Oligosaccharide core”, which is closely linked to Lipid A, it could be the option to choose. Moreover, oligo saccharides are involved in toxicity responses in several microorganisms
.
Answer:
is the correct equation for beta decay.
Explanation:
When a beta particle, that is,
is emitted in a radioactive decay then it is known as beta decay.
Therefore, beta decay of Polonium-218 is as follows.
Therefore, we can conclude that
is the correct equation for the given beta decay.
Answer:
Option 3. The catalyst does not affect the enthalpy change (
) of a reaction.
Explanation:
As its name suggests, the enthalpy change of a reaction (
) is the difference between the enthalpy of the products and the reactants.
On the other hand, a catalyst speeds up a reaction because it provides an alternative reaction pathway from the reactants to the products.
In effect, a catalyst reduces the activation energy of the reaction in both directions. The reactants and products of the reaction won't change. As a result, the difference in their enthalpies won't change, either. That's the same as saying that the enthalpy change
of the reaction would stay the same.
Refer to an energy profile diagram. Enthalpy change of the reaction
measures the difference between the two horizontal sections. Indeed, the catalyst lowered the height of the peak. However, that did not change the height of each horizontal section or the difference between them. Hence, the enthalpy change of the reaction stayed the same.
It should be the digestive system as it absorbs the nutrients of the food into your body.
Answer:
0.287 mole of PCl5.
Explanation:
We'll begin by calculating the number of mole in 51g of Cl2. This is illustrated below:
Molar mass of Cl2 = 2 x 35.5 = 71g/mol
Mass of Cl2 = 51g
Number of mole of Cl2 =..?
Mole = Mass /Molar Mass
Number of mole of Cl2 = 51/71 = 0.718 mole
Next, we shall write the balanced equation for the reaction. This is given below:
P4 + 10Cl2 → 4PCl5
Finally, we determine the number of mole of PCl5 produced from the reaction as follow:
From the balanced equation above,
10 moles of Cl2 reacted to produce 4 moles of PCl5.
Therefore, 0.718 mole of Cl2 will react to produce = (0.718 x 4)/10 = 0.287 mole of PCl5.
Therefore, 0.287 mole of PCl5 is produced from the reaction.