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Alex787 [66]
3 years ago
11

Is direction as important as distance in describing motion?

Physics
2 answers:
blagie [28]3 years ago
8 0

Answer:

No, distance is more important.

lianna [129]3 years ago
4 0

Answer:

Average Velocity and Time The case of motion in one dimension one direction is a good starting point for the description of motion.

distance is

-Hops

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How to find angular velocity from linear velocity and radius.
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ω=v/r.

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<em><u>angular velocity= linear velocity/radius</u></em>

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Which theory suggests that the moon and the earth formed at the same time from dust and the solar nebula that formed the sun?
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Answer: The correct answer is option(B.).

Explanation:

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Where as capture theory suggests that the moon is an asteroid which was formed or created somewhere else in a solar system. And when the moon approached the earth planet it got captured by the earth's gravitational field.

Impact theory explains the formation of moon by the catastrophic collision between the earth and any planet half the size of earth's size.

Synchronous theory sheds the light on the rotation time, revolution time and sides of moon located from the surface of the earth.

Hence, the correct answer is option(B).

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3 years ago
Two particles are traveling through space. At time t the first particle is at the point (−1 + t, 4 − t, −1 + 2t) and the second
Pie

Answer:

Yes, the paths of the two particles cross.

Location of path intersection = ( 1 , 2 , 3)

Explanation:

In order to find the point of intersection, we need to set both locations equal to one another. It should be noted however, that the time for each particle can vary as we are finding the point where the <u>paths</u> meet, not the point where the particles meet themselves.

So, we can name the time of the first particle T_F ,  and the time of the second particle T_S.

Setting the locations equal, we get the following equations to solve for T_F and T_S:

(-1 + T_F) = (-7 + 2T_S)                     Equation 1

(4 - T_F) = (-6 + 2T_S)                        Equation 2

(-1 + 2T_F) = (-1 + T_S)                     Equation 3

Solving these three equations simultaneously we get:

T_F = 2 seconds

T_S = 4 seconds

Since, we have an answer for when the trajectories cross, we know for a fact that they indeed do cross.

The point of crossing can be found by using the value of T_F or T_S in the location matrices. Doing this for the first particle we get:

Location of path intersection = ( -1 + 2 , 4 - 2 , -1 + 2(2) )

Location of path intersection = ( 1 , 2 , 3)

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