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1 year ago

H₂O is the Lewisin thefollowing reaction.SO3(aq) + 2H₂O(1) = H₂SO3(aq) + 2OH- (aq)ABacidbase

Chemistry

1 answer:

svet-max [94.6K]1 year ago

8 0

The definition of a Lewis acid and base is: Acid is any substance that can accept a pair of nonbonding electrons, while that a Base is a species that contains a nonbonding pair of electrons, and in the reaction in the question:

SO3 + H2O -> H2SO3 + 2 OH-

We have SO3 as the conjugate base of the acid H2SO3 and H2O is acting as an acid in this occasion, therefore the answer is Acid

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Answer:

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Explanation:

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$P = \int_{x_{1}}^{x_{2}} \psi^{2} dx$

$P = \int_{x_{1}}^{x_{2}} (\sqrt \frac{2}{L} sin(\frac{n \pi x}{L}))^{2} dx$

$P = \frac{2}{L} \int_{x_{1}}^{x_{2}} (sin^{2}(\frac{n \pi x}{L}) dx$

Evaluating the above integral from x₁ = 0 to x₂ = L/8 and solving it, we have:

$P = \frac{2}{L} [\frac{L}{16} (1 - 4\frac{sin(\frac{n \pi}{4})}{n \pi})]$

$P = \frac{1}{8} (1 - 4\frac{sin(\frac{n \pi}{4})}{n \pi})$

Solving for n=4:

$P = \frac{1}{8} (1 - 4\frac{sin(\frac{4 \pi}{4})}{4 \pi})$

$P = \frac{1}{8} (1 - \frac{sin (\pi)}{\pi})$

$P = \frac{1}{8}$

I hope it helps you!

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