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OLEGan [10]
1 year ago
8

H₂O is the Lewisin thefollowing reaction.SO3(aq) + 2H₂O(1) = H₂SO3(aq) + 2OH- (aq)ABacidbase

Chemistry
1 answer:
svet-max [94.6K]1 year ago
8 0

The definition of a Lewis acid and base is: Acid is any substance that can accept a pair of nonbonding electrons, while that a Base is a species that contains a nonbonding pair of electrons, and in the reaction in the question:

SO3 + H2O -> H2SO3 + 2 OH-

We have SO3 as the conjugate base of the acid H2SO3 and H2O is acting as an acid in this occasion, therefore the answer is Acid

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The relationship between mass and volume can be easily determined using density; for example, the mass of a body is equal to its volume multiplied by the density (M = Vd), whereas the volume is equal to the mass divided by the density (V = M/d). The ball filled with nitrogen will not float in the air because total density of filled ball is greater than the density of an air. Density of the evacuated ball D = 0.214 g/L

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What is the limiting reactant when 4 mol P4 and 4 mol S8 react.
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Taking into account the reaction stoichiometry, P₄ will be the limiting reagent.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

8 P₄ + 3 S₈ → 8 P₄S₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

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<h3>Limiting reagent</h3>

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

<h3>Limiting reagent in this case</h3>

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 3 moles of S₈ reacts with 8 moles of P₄, 4 moles of S₈ reacts with how many moles of P₄?

moles of P_{4} =\frac{4 moles of S_{8} x8 moles of P_{4} }{3 moles of S_{8}}

<u><em>moles of P₄= 10.667 moles</em></u>

But 10.667 moles of P₄ are not available, 4 moles are available. Since you have less amount of moles than you need to react with 4 moles of S₈, P₄ will be the limiting reagent.

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