What is the man’s weight on Mars where the acceleration due to gravity is 3.7 m/s2?

Below are the reduction half reactions for chemolithoautotrophic nitrification, where ammonia is a source of electrons and energ

SSSSS [86.1K]

Answer: The molecules of oxygen gas that will be reduced to water are 42 molecules

Explanation:

We are given:

$E^o_{(NO_2^-/NH_4)}=-0.41V\\E^o_{(O_2/H_2O)}=0.82V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, oxygen will undergo reduction reaction will get reduced.

$NH_4$ will undergo oxidation reaction and will get oxidized.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

The half reactions follows:

Oxidation half reaction: $NH_4\rightarrow NO_2^-+6e^-$ ( × 4)

Reduction half reaction: $O_2+4e^-\rightarrow 2H_2O$ ( × 6)

Overall reaction: $4NH_4+6O_2\rightarrow 4NO_2^-+12H_2O$

We are given:

Molecules of $NH_4$ = 28

By Stoichiometry of the reaction:

4 molecules of $NH_4$ reacts with 6 molecules of oxygen gas

So, 28 molecules of $NH_4$ will react with = $\frac{6}{4}\times 28=42$ molecules of oxygen gas

Hence, the molecules of oxygen gas that will be reduced to water are 42 molecules

4 0

3 years ago

La fórmula correcta del óxido salino de estaño es: *

BaLLatris [955]

No hao luh cub chi wuh

3 0

3 years ago

An exothermic reaction is a chemical reaction that produces _____.

lana66690 [7]

I pretty sure the answer is a

8 0

3 years ago

What is the mass of carbon in 500. g of octane?

denis23 [38]

The answer is: the mass of carbon is 420.6 grams.

m(C₈H₁₈) = 500 g; mass of octane.

M(C₈H₁₈) = 114.22 g/mol; molar mass of octane.

n(C₈H₁₈) = m(C₈H₁₈) ÷ M(C₈H₁₈).

n(C₈H₁₈) = 500 g ÷ 114.22 g/mol.

n(C₈H₁₈) = 4.38 mol; amount of octane.

In one molecule of octane, there are eight carbon atoms:

n(C) = 8 · n(C₈H₁₈).

n(C) = 8 · 4.38 mol.

n(C) = 35.02 mol; amount of carbon.

m(C) = 35.02 mol · 12.01 g/mol.

m(C) = 420.6 g; mass of carbone.

5 0

3 years ago

Hydrogen peroxide decomposes to water and oxygen at constant pressure by the following reaction: 2H2O2(l) → 2H2O(l) + O2(g) ΔH =

Mashcka [7]

Answer: The amount of heat released is -7.203 kJ

Explanation:

The given chemical equation follows:

$2H_2O_2(l)\rightarrow 2H_2O(l )+O_2(g);\Delta H=-196kJ$

To calculate the enthalpy change for 1 mole of the hydrogen peroxide, we use unitary method:

When 2 moles of hydrogen peroxide is reacted, the enthalpy of the reaction is -196 kJ

So, when 1 mole of hydrogen peroxide will react, the enthalpy of the reaction will be $\frac{-196}{2}\times 1=-98kJ$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of hydrogen peroxide = 2.50 g

Molar mass of hydrogen peroxide = 34 g/mol

Putting values in above equation, we get:

$\text{Moles of hydrogen peroxide}=\frac{2.50g}{34g/mol}=0.0735mol$

To calculate the heat of the reaction, we use the equation:

$\Delta H_{rxn}=\frac{q}{n}$

where,

$q$ = amount of heat released

n = number of moles = 0.0735 moles

$\Delta H_{rxn}$ = enthalpy change of the reaction = -98 kJ/mol

Putting values in above equation, we get:

$-98kJ/mol=\frac{q}{0.0735mol}\\\\q=(-98kJ/mol\times 0.0735mol)=-7.203kJ$

Hence, the amount of heat released is -7.203 kJ

8 0

3 years ago