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2 years ago

An SN2 reaction is a type of __in which the nucleophile attacks the electrophile _a leaving group leaves.

Chemistry

1 answer:

mars1129 [50]2 years ago

6 0

Answer:

Nucleophilic reaction

and

Explanation:

A nucleophilic reaction is a type of reaction that involves attack of a specie having a negative charge or a lone pair of electrons on a positive center. This negatively charged specie or specie having a lone pair of electrons is called a nucleophile.

An SN2 reaction is a bimolecular, concerted nucleophilic reaction that leads to inversion of configuration at the carbon center. The leaving group is the group that departs from the frontside of the molecule as the nucleophile attacks from the backside.

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I can't leave till I answer please help!!

vovikov84 [41]

I think the answer would be 2

3 0

2 years ago

Read 2 more answers

3. How many moles of solute are present in a 2300 mL solution of 0.68 M MgSO.?

Nostrana [21]

There are 1.56 moles of solute present in a 2300 mL solution of 0.68M MgSO4.

<h3>How to calculate number of moles?</h3>

The number of moles of a substance can be calculated by using the following formula:

molarity = no. of moles / volume

According to this question, a volume of 2300 mL solution is contained in 0.68 M MgSO4. The number of moles is calculated as follows:

no of moles = 0.68M × 2.3

no. of moles = 1.56

Therefore, there are 1.56 moles of solute present in a 2300 mL solution of 0.68M MgSO4.

Learn more about moles at: brainly.com/question/12127540

8 0

2 years ago

Starting with 250 mL of a 0.250 M solution of HBr; a) Calculate the initial pH of the solution.b) Calculate the pH after adding

maxonik [38]

Answer:

pH = 0.602

pH = 1.5

pH = 7

pH = 12.1

Explanation:

a ) To calculate the pH, use the following equation:

pH = -log [H+]

Hbr is a strong acid, so the [H+] concentration can be calculated as follow:

[HBr] = 0.250 M

As acid Hbr:

Hbr = H+ + Br-

As strong acid HBr dissociates at all, so

[HBr] = [H+] = 0.250 M

So the pH:

pH = -log [0.250 M] = 0.602

b) Calculate the pH after adding 250 mL of 0.125M NaOH

In this point, the reactions starts:

HBr + NaOH = H2O + NaBr

- First, we gonna find the mol of each reactant:

HBr:

mol = [M] × L

mol = 0.250 M × 0.250 L

mol = 0.0625 mol HBr

NaOH:

mol = [M] × L

mol = 0.125 M × 0.250L

mol = 0.03125 mol NaOH

In base on the reaction, it’s needed 1 mol of NaOH to neutralize 1 mole of HBr, so to neutralize 0.0625 moles of HBr its needed 0.0625 mol of NaOH:

0.0625 mol HBr – 0.03125 mol HBr = 0.03125 mol HBr

These are the moles free in the solution, and we going to use them to calculate the pH:

pH = -log [ H]

pH = - log [ 0.03125 ] = 1.5

c) Calculate the pH after adding 500 mL of 0.125M NaOH

NaOH:

mol = [M] × L

mol = 0.125 M × 0.500L

mol = 0.0625 mol NaOH

In base on the reaction, it’s needed 1 mol of NaOH to neutralize 1 mole of HBr, so to neutralize 0.0625 moles of HBr its needed 0.0625 mol of NaOH:

0.0625 mol HBr – 0.0625 mol HBr = 0 HBr

pH = 7

d) Calculate the pH after adding 600 mL of 0.125M NaOH.

NaOH:

mol = [M] × L

mol = 0.125 M × 0.600L

mol = 0.075 mol NaOH

In base on the reaction, it’s needed 1 mol of NaOH to neutralize 1 mole of HBr, so to neutralize 0.0625 moles of HBr its needed 0.0625 mol of NaOH:

0.075 mol NaOH – 0.0625 mol NaOH = 00125 NaOH

These are the moles free in the solution, and we going to use them to calculate the pH:

pOH = -log [ OH]

pOH = - log [ 0.0125 ] = 1.90

pH + pOH = 14

pH = 14- pOH = 14 – 1.90 = 12.1

4 0

3 years ago

Identify the species that is oxidized and the species that is reduced in this reaction. Also, identify the oxidizing agent and t

natulia [17]

Answer:

Given the equation of the reaction below:

3Cl₂(g) + 2Al(s) → 6Cl⁻(aq) + 2Al³⁺(aq)

The oxidized species is aluminum, Al, as its oxidation number increases from zero to +3. Al therefore, acts as the reducing agent.

Also, the reduced species is chlorine gas, Cl₂, as its oxidation number decreases from zero to -1. Therefore, Cl, is the reducing agent.

Note: the question is incomplete. a related question is given as follows; Identify the species oxidized, the species reduced, the oxidizing agent and the reducing agent in the following electron transfer reaction. 3Cl2 + 2Al → 6Cl - + 2Al3+ species oxidized:

Explanation:

An oxidation is a process in which there is a loss of electrons whereas reduction is a process involving the gain of electrons. A redox reaction is a reaction in which oxidation and reduction processes occur concurrently and to the same extent.

In a redox reaction reaction, the substance which is oxidized serves as the reducing agent by donating electrons to the substance which is reduced. On the other hand, the substance which is reduced serves as the oxidizing agent by accepting the electrons donated by the substance which is oxidized. In oxidation, the oxidation number of the substance oxidized increases, whereas in reduction, the oxidation number of the substance decreases.

For example, given the equation of the reaction below:

3Cl₂(g) + 2Al(s) → 6Cl⁻(aq) + 2Al³⁺(aq)

The oxidized species is aluminum, Al, as its oxidation number increases from zero to +3. Al therefore, acts as the reducing agent.

Also, the reduced species is chlorine gas, Cl₂, as its oxidation number decreases from zero to -1. Therefore, Cl, is the reducing agent.

6 0

2 years ago

Volume of 100ml. it’s density is 0.15g/ml. what is its mass?

11Alexandr11 [23.1K]

$V=100mL\\
d=0,15\frac{g}{mL}\\\\
m=dV=0,15\frac{g}{mL}*100mL=15g$

3 0

3 years ago

Read 2 more answers

An SN2 reaction is a type of ________in which the nucleophile attacks the electrophile _______a leaving group leaves.

An SN2 reaction is a type of __in which the nucleophile attacks the electrophile _a leaving group leaves.