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kozerog [31]
3 years ago
8

Jasmine broke the antenna on her radio receiver. How will this most likely affect Jasmine’s radio?

Physics
1 answer:
Alexeev081 [22]3 years ago
4 0

Jasmine will not be able to receive radio connection and when she decides to use her radio, there may be much static noises

she will still be able to use items such as Aux, CD, and tapes

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It's                      -10                  yo

the              right          answer
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3 years ago
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Why did the producers and director decide to have the girls run outside to the water during the climactic moments of Act Three?
jolli1 [7]
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Suppose that a parallel-plate capacitor has circular plates with radius R = 25 mm and a plate separation of 4.7 mm. Suppose also
ozzi

Answer:

a) B_{max} = 1.784*10^{-12}

Explanation:

Given paraeters are:

R = 25 cm

d = 4.7 mm

f = 60 Hz

V_m = 160 V

a) V = V_msin(2\pi ft)

Where f = 60 Hz and V_m = 160 V

E =V/d= \frac{V_msin(2\pi ft)}{d}

For r = R

A = \pi R^2

Since \Phi_E = EA

\Phi_E=\frac{\pi R^2V_msin(2\pi ft) }{d}

From Ampere's Law:

\int B.ds = \mu_0\epsilon_0\frac{d\Phi_E}{dt} + \mu_0I_{encl} where I_{encl}=0

So at r = R,

B.2\pi R = \mu_0\epsilon_0\frac{d\Phi_E}{dt}\\B.2\pi R = \mu_0\epsilon_0\frac{2\pi^2fR^2V_mcos(2\pi ft)}{d}\\B = \frac{\mu_0\epsilon_0\pi fRV_mcos(2\pi ft)}{d}

For maximum B, cos(2πft) = 1. Hence,

B_{max}=\frac{\mu_0\epsilon_0\pi fRV_m}{d}=\frac{4\pi*10^{-7}*8.85*10^{-12}*\pi*60*0.025*160}{4.7*10^{-3}}=1.784*10^{-12} T

b) From r = 0 to r = R = 0.025 m, by Ampere's Law, the equation will be:

B = \frac{\mu_0\epsilon_0\pi fR^2V_m}{rd}

From r = R = 0.025 m to r = 0.1 m, by Ampere's Law, the equation will be:

B = \frac{\mu_0\epsilon_0\pi fRV_m}{d}

The plot is given in the attachment.

5 0
4 years ago
The take-up reel of a cassette tape has an average radius of 1.5 cm. Find the length of tape (in meters) that passes around the
Rudik [331]

Answer:

 1.28 m

Explanation:

Given;

Radius, r = 1.5 cm =  0.015 m

Time, t = 19 s

Average angular speed = 4.5 rad/s

Consider a point when the tape is moving at a constant velocity along the circumference of the circular reel of radius  r. The linear velocity  v at this point is given by;

                                      v = rω                           ----(1)

Where

v is the linear velocity of the circular motion

r is the radius of the reel

ω is the the angular velocity.

At a point the tap undergoes a linear motion before passing round the reel of the cassette. The linear velocity v at this point is given by;

                                v = L/t                          ----(2)

where;

v is the velocity of the linear motion

L is the length of the tape (distance covered by the tape)

t is the time taken

Equating equation(1) and equation (2)

                       L/t = rω

                       L = rωt

Substituting the given values,

                       L = 0.015 × 4.5 × 19

                       L = 1.2825 m

                       L = 1.28 m

 

4 0
3 years ago
A biker rides on an upward-sloped road inclined at a 15.0° angle with the horizontal. If he moves at a constant speed of 2.0 met
IrinaVladis [17]

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