It is trajectory acceleration. A friction track is a device to study motion in low friction environments, I believe. Does this help?
Answer:
1.8nA
Explanation:
I = dq/dt
I = 9.0 × 10 ^-12 / 0.5 × 10^-3
I = 1.8 × 10× 10^-8
I = 1.8nA
Answer:
its correct no need to change anything :))
Answer:
a) 10.54 sec
b) 284.58 m
c) 29.406 m/s
d) 39.92 m/s
Explanation:
Given data:
velocity of spacecraft = 27.0 m/s
rate of free fall acceleration is 2.79 m/s^2
distance of moving aircraft from mooon surface is 155 m
a. from kinematic eqaution of motion we have

where y = 155 m
Vi = 0 as this relation is for vertical motion, so the 27.0 m/s is not included
and a = 2.79 m/s^2.
Solving for t we get
t = 10.54 sec
b.
we know that 


c. from the kinematic formula
v = u + at

v = 29.4066 m/a
d. 
v = 39.92 m/s
Voltage=Energy/Charge, V=E/Q
V in volts V, E in joules J, Q in coulombs C.
or
Voltage= Current×Resistance, V=IR
V in volts V, I in amperes A and R in ohms Ω