I like playing basketball. So I'm the object in motion. Until an unbalanced force comes and hits me I fall and stay at rest.
Answer:
Spherical mirror is a mirror with a curved reflecting surface.
<span>The number in front is the number of molecules (or atoms) taking part in the (balanced) chemical reaction equation.</span>
Answer:
v = 384km/min
Explanation:
In order to calculate the speed of the Hubble space telescope, you first calculate the distance that Hubble travels for one orbit.
You know that 37000 times the orbit of Hubble are 1,280,000,000 km. Then, for one orbit you have:
![d=\frac{1,280,000,000km}{37,000}=34,594.59km](https://tex.z-dn.net/?f=d%3D%5Cfrac%7B1%2C280%2C000%2C000km%7D%7B37%2C000%7D%3D34%2C594.59km)
You know that one orbit is completed by Hubble on 90 min. You use the following formula to calculate the speed:
![v=\frac{d}{t}=\frac{34,594.59km}{90min}=384.38\frac{km}{min}\approx384\frac{km}{min}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bd%7D%7Bt%7D%3D%5Cfrac%7B34%2C594.59km%7D%7B90min%7D%3D384.38%5Cfrac%7Bkm%7D%7Bmin%7D%5Capprox384%5Cfrac%7Bkm%7D%7Bmin%7D)
hence, the speed of the Hubble is approximately 384km/min
Answer:
B. A repulsive force of 8.0*10^3 N.
Explanation:
As we know by Coulomb's law that the electrostatic force between two charges is given as
![F = \frac{kq_1q_2}{r^2}](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7Bkq_1q_2%7D%7Br%5E2%7D)
here we know that
![q_1 = -2 \times 10^2 C](https://tex.z-dn.net/?f=q_1%20%3D%20-2%20%5Ctimes%2010%5E2%20C)
![q_2 = -4 \times 10^{-8} C](https://tex.z-dn.net/?f=q_2%20%3D%20-4%20%5Ctimes%2010%5E%7B-8%7D%20C)
r = 3.0 m
now we have
![F = \frac{(9 \times 10^9)(2 \times 10^2)(4\times 10^{-8})}{3^2}](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7B%289%20%5Ctimes%2010%5E9%29%282%20%5Ctimes%2010%5E2%29%284%5Ctimes%2010%5E%7B-8%7D%29%7D%7B3%5E2%7D)
![F = 8000 N](https://tex.z-dn.net/?f=F%20%3D%208000%20N)
since both charges are similar charges so they will repel each other by the force we calculated above so correct answer will be
B. A repulsive force of 8.0*10^3 N.