.75(m/s)^2
Use this picture
If you know the two on the bottom you multiply them but if you only know the top and one on the bottom you divide
Answer:
You are given that the mass of the clock M is 95 kg.
This is true whether the clock is in motion or not.
Fs is the frictional force required to keep the clock from moving.
Thus Fk = uk W = uk M g the force required to move clock at constant speed. (the kinetic frictional force)
uk = 560 N / 931 N = .644 since the weight of the clock is 931 N (95 * 9.8)
us is the frictional force requited to start the clock moving
us = static frictional force = 650 / 931 -= .698
Answer:
the resulting angular speed after she pulls her hand inwards in (rad/s) is 27.02 rad/s
Explanation:
Given that :
the initial angular speed 
Initial rotational inertia 
Final angular speed 
Final rotational inertia 
According to conservation of momentum :
Initial momentum = final momentum
To rad/s ; we have:
Therefore the resulting angular speed after she pulls her hand inwards in (rad/s) = 27.02 rad/s
