The answer you’re looking for is
D. Gamma rays
Enjoy the rest of your day/night :)
Average speed is defined as total distance moved in total interval of time
so it is given as
![v_{avg} = \frac{distance}{time}](https://tex.z-dn.net/?f=v_%7Bavg%7D%20%3D%20%5Cfrac%7Bdistance%7D%7Btime%7D)
now here is we show distance by "d" and time by"t"
then we will have mathematical expression as follows
![v = \frac{d}{t}](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7Bd%7D%7Bt%7D)
Perfectly inelastic collision is type of collision during which two objects collide, stay connected and momentum is conserved. Formula used for conservation of momentum is:
![m_{1} * v_{1} + m_{2} * v_{2} = m_{1} * v'_{1} + m_{2} * v'_{2}](https://tex.z-dn.net/?f=%20m_%7B1%7D%20%2A%20v_%7B1%7D%20%2B%20%20m_%7B2%7D%20%2A%20v_%7B2%7D%20%3D%20%20m_%7B1%7D%20%2A%20v%27_%7B1%7D%20%2B%20%20m_%7B2%7D%20%2A%20v%27_%7B2%7D)
In case of perfectly inelastic collision v'1 and v'2 are same.
We have following information:
m₁=3 kg
m₂=? kg
v₁=x m/s
v₂=0 m/s
v'1 = v'2 = 1/3 * v₁
Now we insert given information and solve for m₂:
3*v₁ + 0*? = 3*1/3*v₁ + m₂*1/3*v₁
3v₁ = v₁ + m₂*1/3*v₁
2v₁ = m₂*1/3*v₁
2 = m₂*1/3
m₂= 6kg
Mass of second mud ball is 6kg.
Hey There,
Question: "<span>A student gives a brief push to a block of dry ice. A moment later, the block moves across a very smooth surface at a constant speed. When drawing the free body diagram for the block of dry ice moving at a constant speed, the forces that should be included are: (select all that apply)"
Answer: C. Force Of Friction
B. Force
If This Helps May I Have Brainliest?</span>