The main difficulty with multiple star systems such as Alpha Centauri as places to look for life is that: _________

Physics

1 answer:

Leona [35]1 year ago

8 0

Answer:

The conditions for life are extremely specific and the search is extremely broad.

Explanation:

in order to sustain life, the planet has to have water.

Too hot and the water will evaporate too cold and the water will freeze, this is based on the planet's distance from the sun and its solar mass. (The mass compared to our sun) If the solar mass is double that of our sun then the planet would have to be double the distance from the sun in order to sustain life and keep the water from evaporating. Let me Know if This helps

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Irina-Kira [14]

We simply asked to name three uses for mercury.
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It is also used to form an amalgam which is the result of its combination with silver or gold. Mercury has been used to mine gold and silver. This application has also been phased out.
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2 years ago

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TRUE OR FALSE! PLZ HELP

Ksju [112]

Answer:

True

Explanation:

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2 years ago

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vladimir2022 [97]

Answer:

Directly proportional: as one amount increases another amount increases at the ... The "constant of proportionality" is the value that relates the two amounts ... Example: y is directly proportional to x, and when x=3 then y=15. ... Speed and travel time are Inversely Proportional because the faster we go the shorter the time.

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2 years ago

An automobile traveling 95 km/h overtakes a 1.30-km-long train traveling in the same direction on a track parallel to the road.

SOVA2 [1]

Answer:

Same direction: t=234s; d=6.175Km

Opposite direction: t=27.53s; d=0.73Km

Explanation:

If the automobile and the train are traveling in the same direction, then the automobile speed relative to the train will be $v_{AT}=v_A-v_T$ (the train must see the car advancing at a lower speed), where $v_A$ is the speed of the automobile and $v_T$ the speed of the train.

So we have $v_{AT}=(95km/h)-(75Km/h)=20Km/h$ .

So the train (anyone in fact) will watch the automobile trying to cover the lenght of the train L at that relative speed. The time required to do this will be:

$t = \frac{L}{v_{AT}} = \frac{1.3Km}{20Km/h} = 0.065h=234s$

And in that time the car would have traveled (relative to the ground):

$d=v_At=(95Km/h)(0.065h)=6.175Km$

If they are traveling in opposite directions, we have to do all the same but using $v_{AT}=v_A+v_T$ (the train must see the car advancing at a faster speed), so repeating the process: