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mojhsa [17]
4 years ago
8

sam bought 2 1/4 pounds of swiss cheese 1 1/2 pounds of cheddar at the deli how many pounds of cheese did sam buy altogether

Chemistry
2 answers:
statuscvo [17]4 years ago
8 0
2 1^/4 + 11^/2 = 9^/4 + 3^/2 = 9^/4 + 6^/4 = 15^/4 = 3 3^/4



Lostsunrise [7]4 years ago
4 0

Answer:

\frac{15}{4} pounds of cheese Sam had bought altogether.

Explanation:

Mass of Swiss cheese bought by  Sam = 2\frac{1}{4}=\frac{9}{4} pounds

Mass of cheddar cheese bought by  Sam = 1\frac{1}{2}=\frac{3}{2} pounds

Total mas of cheese bought by Sam:

\frac{9}{4} pounds+\frac{3}{2} pounds

=\frac{9\times 2+3\times 4}{4\times 2} pounds=\frac{30}{8} pounds=\frac{15}{4} pounds

\frac{15}{4} pounds=3\frac{3}{4} pounds

\frac{15}{4} pounds of cheese Sam had bought altogether.

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The amount of heat Q can be calculated using following formula.

Q = m \times C \times \bigtriangleup T

Where Q is the amount of heat required = 300 J

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ΔT is the change in temperature = 12°C

C is the specific heat of the substance.

We want to solve for C, so the equation for Q is modified as follows.

C = \frac{Q}{m \times \bigtriangleup T}

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The given parameters are;

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The electrochemical equivalent, 'Z', of an element or a substance is the mass, 'm', of the element or substance deposited by one coulomb of electricity, which is equivalent to a 1 ampere current flowing for a period of 1 second

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