Answer:
2.89 g/cm^3
Explanation:
Since density equals mass over volume (or also seen as
), simply divide 66.5 grams by 23.0 cm. This will output an answer of 2.89 g/cm^3.
The second brother Brother because he is much heavier and therefore has more energy to be released hope this helps
Answer:
%
Explanation:
The ethanol combustion reaction is:
→
If we had the amount (x moles) of ethanol, we would calculate the oxygen moles required:

Dividing the previous equation by x:

We would need 3.30 oxygen moles per ethanol mole.
Then we apply the composition relation between O2 and N2 in the feed air:

Then calculate the oxygen moles number leaving the reactor, considering that 0.85 ethanol moles react and the stoichiometry of the reaction:

Calculate the number of moles of CO2 and water considering the same:


The total number of moles at the reactor output would be:

So, the oxygen mole fraction would be:
%