Why is work and potential energy the same thing

1 answer:

5 0

Potential energy and work done are the same thing as much as kinetic energy and work done are the same thing. Potential energy is a state of the system, a way of storing energy as of virtue of its configuration or motion, while work done in most cases is a way of chaning this energy from one body to another.

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a cart is loaded with a brick and pulled up at a constant speed along an inclined plane to the height of a seattop. if the mass

Fudgin [204]

Answer:

6 J

Explanation:

Gravitational Potential Energy can be calculated using the formula:

PE = mgh

where m is mass of object in kg

g is the gravitational acceleration of 10 m/s^2

h is the height at which object is thrown in m.

Hence, by substituting in the values, we get:

GPE = (4.0)(10)(0.15)

6 J

Hence, the potential energy is 6 J.

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If a substance containing charged ions and electrons can be compressed so that the particles have less space between them, the s

HACTEHA [7]

It’s b plasma because plasma is a hot ionized gas

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2 years ago

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A 62-kg man standing on a scale in an elevator notes that as the elevator rises, the scale reads 821 N. What is the acceleration

FromTheMoon [43]

Answer:

Acceleration of the elevator = 13.242 m/s2.

Explanation:

Force is defined as the push or pull on an object with mass in kg that causes a change velocity. Force as a vector means it has both magnitude and direction.

Mathematically,

F = M*a

Where

F = force in Newton.

M = mass of the object in kg.

a = acceleration due to gravity in 9.81 m/s2.

Acceleration of the elevator = 821/62

= 13.242 m/s2.

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3 years ago

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When a 25000-kg fighter airplane lands on the deck of the aircraft carrier, the carrier sinks 0.23cm deeper into the water.

Genrish500 [490]

Answer:

10604 square meters

Explanation:

0.23 cm = 0.0023m

Assume the carrier has a shape of a rectangular box. When the carrier sinks 0.0023m deeper into water, the extra volume submerged into water is the same as the extra water volume being replaced. This extra volume would add an additional buoyant force to counter balance the extra weight created by the 25000 kg fighter.

With g being constant, the mass of the extra water displaced is the same as the mass of the fighter airplane $m_f$ . And mass of the water displaced is its volume V times its density $\rho$