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dolphi86 [110]
2 years ago
12

WILL AWARD BEST ANSWER! find the current flowing across the 30 ohm resistor i = _ a

Physics
1 answer:
Lelu [443]2 years ago
6 0

0.143 A

Explanation:

The total resistance of the circuit is

r =  \frac{(40)(30)}{40 + 30}  +  \frac{(50)(20 + 10)}{50 + (20 + 10)}   \\ = 35.89 \: ohms

so the total current is

Itotal= V/R = 9V/35.89 ohms

= 0.25 A

To find the voltage drop across the 30-ohns resistor, use

V = Itotal × (combined resistance of 40 30)

= 0.25 A × 17.14 ohms = 4.285 volts

so the current through the 30-ohm resistor is

I = (voltage drop)/30-ohms

= (4.285 V)/(30 ohms)

= 0.143 A

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Explanation:

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3 years ago
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The center of mass of the system is the point at which the total mass of the system could be concentrated without changing the _
Sveta_85 [38]

  The centre of mass of the system is the point at which the total

  mass of system could be concentrated without changing the moment

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Centre of Mass is the point at which the whole mass of the system

is assumed to be concentrated.

 The general formula for the COM is:

              xₙ =  Σmₐxₐ / Σmₐ         where,  a = 1,2,3.........n

  Here the term Σ mₐ xₐ is called the first moment of the system and the

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    Therefore, from this theory we can say that the moment of the system

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  Hence, The centre of mass of the system is the point at which the total

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   learn more about centre of mass here:

             brainly.com/question/3454419

                #SPJ4

8 0
1 year ago
A 56.6-kg crate rests on a level floor at a shipping dock. The coefficients of static and kinetic friction are 0.517 and 0.260,
kifflom [539]

Answer:

Explanation:

Magnitude of frictional force = μ mg

μ is either static or kinetic friction.

To start the crate moving , static friction is calculated .

a ) To start crate moving , force required = μ mg where μ is coefficient of static friction .

force required =.517 x 56.6  x 9.8 = 286.76  N .

b ) to  slide the crate across the dock at a constant speed , force required

= μ mg where μ is coefficient of kinetic  friction , where μ is kinetic friction

= .26 x 56.6  x 9.8 = 144.21 N .

3 0
2 years ago
A vessel that contains a gas has two pressure gauges attached to it. One contains liquid mercury, and the other an oil such as d
castortr0y [4]

Answer:

Pressure of the gas = 12669 (Pa) and height of the oil is 1,24 meters

Explanation:

First, we can use the following sketch for an easy understanding, in the attached image we can see the two pressure gauges the one with mercury to the right and the other one with oil to left. We have all the information needed in the mercury pressure gauge, so we can determine the pressure inside the vessel because the fluid is a gas it will have the same pressure distributed inside the vessel (P1).

Since P1 = Pgas, we can use the same formula, but this time we need to determine the height of the column of oil in the pressure gauge.

The result is that the height of the oil column is higher than the height of the one that uses mercury, this is due to the higher density of mercury compared to oil.

Note: the information given in the units of the fluids is not correct because the density is always expressed in units of (mass /volume)

4 0
3 years ago
A harmonic force of maximum value 25 N and frequency of 180 cycles>min acts on a machine of 25 kg mass. Design a support syst
kramer

Answer:

registrar y de h2rhrjlekeek tert2h2jwkwlwlwlwlwlwñlwk

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3 years ago
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