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dolphi86 [110]
3 years ago
12

WILL AWARD BEST ANSWER! find the current flowing across the 30 ohm resistor i = _ a

Physics
1 answer:
Lelu [443]3 years ago
6 0

0.143 A

Explanation:

The total resistance of the circuit is

r =  \frac{(40)(30)}{40 + 30}  +  \frac{(50)(20 + 10)}{50 + (20 + 10)}   \\ = 35.89 \: ohms

so the total current is

Itotal= V/R = 9V/35.89 ohms

= 0.25 A

To find the voltage drop across the 30-ohns resistor, use

V = Itotal × (combined resistance of 40 30)

= 0.25 A × 17.14 ohms = 4.285 volts

so the current through the 30-ohm resistor is

I = (voltage drop)/30-ohms

= (4.285 V)/(30 ohms)

= 0.143 A

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Answer:

A) v = √[(F₀/m - μ₀) 2x + x2 / L] , b) v = √[2 (F₀ / m - μ₀) +1] L

Explanation:

For this exercise we will use Newton's second law

X axis

           Fo - fr = ma

Y Axis  

          N - W = 0

          N = mg

The equation for the force of friction is

         fr = μ N

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Let's replace

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They ask us the speed of the block, so we must use

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We replace

     v dv = (F₀ / m - μ₀ (1- x/L)) dx

We integrate

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Part B

The velocity for x = L

   v = √(F₀ / m - μ₀) 2L + L2 / L

   v = √[2 (F₀ / m - μ₀) +1] L

8 0
3 years ago
Who provided evidence for the excistenes of a nucleus in an atom
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Ernest Rutherford discovered/proved this in 1911.
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katen-ka-za [31]

Explanation:

we know

v=u-gt

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uy=usin30

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so time taken t=3.07s

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How do you represent a force in a free-body diagram?
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<h3>Spring Constant:</h3>

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The energy is added to the spring when it is compressed. More energy is contained in compressed springs than in uncompressed springs.

One can compute the energy of spring as follows:

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Here, the constant speed of light, c, and the spring's mass, m, is used.

Therefore, since the energy of the compressed spring is higher than the energy of the non-compressed spring and because the mass of the compressed spring is greater than the mass of the non-compressed increases, the energy only depends on the mass of the spring.

As a result, when spring is squeezed, its mass changes.

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