WILL AWARD BEST ANSWER! find the current flowing across the 30 ohm resistor i = _ a
1 answer:
0.143 A
Explanation:
The total resistance of the circuit is
so the total current is
Itotal= V/R = 9V/35.89 ohms
= 0.25 A
To find the voltage drop across the 30-ohns resistor, use
V = Itotal × (combined resistance of 40 30)
= 0.25 A × 17.14 ohms = 4.285 volts
so the current through the 30-ohm resistor is
I = (voltage drop)/30-ohms
= (4.285 V)/(30 ohms)
= 0.143 A
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Answer:
τ = 132.773 lb/in² = 132.773 psi
Explanation:
b = 12 in
F = 60 lb
D = 3.90 in (outer diameter) ⇒ R = D/2 = 3.90 in/2 = 1.95 in
d = 3.65 in (inner diameter) ⇒ r = d/2 = 3.65 in/2 = 1.825 in
We can see the pic shown in order to understand the question.
Then we get
Mt = b*F*Sin 30°
⇒ Mt = 12 in*60 lb*(0.5) = 360 lb-in
Now we find ωt as follows
ωt = π*(R⁴ - r⁴)/(2R)
⇒ ωt = π*((1.95 in)⁴ - (1.825 in)⁴)/(2*1.95 in)
⇒ ωt = 2.7114 in³
then the principal stresses in the pipe at point A is
τ = Mt/ωt ⇒ τ = (360 lb-in)/(2.7114 in³)
⇒ τ = 132.773 lb/in² = 132.773 psi
