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dolphi86 [110]
3 years ago
12

WILL AWARD BEST ANSWER! find the current flowing across the 30 ohm resistor i = _ a

Physics
1 answer:
Lelu [443]3 years ago
6 0

0.143 A

Explanation:

The total resistance of the circuit is

r =  \frac{(40)(30)}{40 + 30}  +  \frac{(50)(20 + 10)}{50 + (20 + 10)}   \\ = 35.89 \: ohms

so the total current is

Itotal= V/R = 9V/35.89 ohms

= 0.25 A

To find the voltage drop across the 30-ohns resistor, use

V = Itotal × (combined resistance of 40 30)

= 0.25 A × 17.14 ohms = 4.285 volts

so the current through the 30-ohm resistor is

I = (voltage drop)/30-ohms

= (4.285 V)/(30 ohms)

= 0.143 A

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please help! find magnitude and direction (the counterclockwise angle with the +x axis) of a vector that is equal to a + c
-BARSIC- [3]

Answer:

Option (2)

Explanation:

From the figure attached,

Horizontal component, A_x=A\text{Sin}37

A_x=12[\text{Sin}(37)]

     = 7.22 m

Vertical component, A_y=A[\text{Cos}(37)]

    = 9.58 m

Similarly, Horizontal component of vector C,

C_x  = C[Cos(60)]

     = 6[Cos(60)]

     = \frac{6}{2}

     = 3 m

C_y=6[\text{Sin}(60)]

    = 5.20 m

Resultant Horizontal component of the vectors A + C,

R_x=7.22-3=4.22 m

R_y=9.58-5.20 = 4.38 m

Now magnitude of the resultant will be,

From ΔOBC,

R=\sqrt{(R_x)^{2}+(R_y)^2}

   = \sqrt{(4.22)^2+(4.38)^2}

   = \sqrt{17.81+19.18}

   = 6.1 m

Direction of the resultant will be towards vector A.

tan(∠COB) = \frac{\text{CB}}{\text{OB}}

                  = \frac{R_y}{R_x}

                  = \frac{4.38}{4.22}

m∠COB = \text{tan}^{-1}(1.04)

             = 46°

Therefore, magnitude of the resultant vector will be 6.1 m and direction will be 46°.

Option (2) will be the answer.

6 0
3 years ago
Communication with submerged submarines via radio waves is difficult because seawater is conductive and absorbselectromagnetic wa
FrozenT [24]

Answer:

D. 4000 km

Explanation:

f = Frequency of wave that is being transmitted = 76 Hz

\lambda = Wavelength of wave that is being transmitted

v = The velocity of electromagnetic waves through air = 3\times 10^8\ m/s

Velocity of a wave is given by

v=f\lambda\\\Rightarrow \lambda=\frac{v}{f}\\\Rightarrow \lambda=\frac{3\times 10^8}{76}\\\Rightarrow \lambda=3947368.42105\ m=3947.36842105 km\approx 4000\ km

Hence, the approximate wavelength of the waves is 4000 km

8 0
3 years ago
4. How do ordinary objects behave in microgravity?
Nikolay [14]

Answer:

Bubbles paused

Explanation:

the air bubble doesn't rise because it is no lighter than the water around it—there's no buoyancy. The droplet doesn't fall from the leaf because there's no force to pull it off. It's stuck there by molecular adhesion.

for instance, onto the International Space Station, gravity becomes negligible, and the laws of physics act differently than here on Earth

On Earth, the buoyancy of the air bubbles causes them to rise to the top together, creating a segregation between air and water. However, in microgravity, nothing forces the air bubbles to interact and thus rise together, Green said.

8 0
3 years ago
Imagine you are mpho:how can you help your friend (phenyo) not to be influenced by media? you really feel she needs some help be
LUCKY_DIMON [66]

One of the ways to help someone not to be influenced by media is:

  • Encourage independent thinking.
  • Let her know that she should make sure the information she is consuming is free from bias and is factual.

<h3>What is Media Influence?</h3>

This refers to the effects and reactions which the mass media has on the people who listen to them by shaping their views and by controlling the narrative.

With this in mind, we can note that if a person is overtly influenced by the media, then such a person lacks independent thinking and becomes emotional by what he watches on the television or reads from an online source.

This can be changed through the encouragement of independent thinking, and the need to check for factual information from the media news and also to focus more on studies.

Read more about media here:
brainly.com/question/26152499

6 0
2 years ago
I need help with these questions.
strojnjashka [21]

I'll go ahead and answer the ones here without an answer. For reference, the half-life formula is <em>final amount = original amount(1/2)^(time/half-life)</em>

<em />

4) 12.5g

x = 100(1/2)^(63/21)

5) 50g

3.125 = x(1/2)^(0.1/0.025)

6) 500g

x = 4000(1/2)^(525/175)

7) 0.24g

0.06 = x(1/2)^(11430/5730)

8) 125g

x = 1000(1/2)^(17100/5700)

Hope this helps! :)

4 0
3 years ago
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