WILL AWARD BEST ANSWER! find the current flowing across the 30 ohm resistor i = _ a
1 answer:
0.143 A
Explanation:
The total resistance of the circuit is
so the total current is
Itotal= V/R = 9V/35.89 ohms
= 0.25 A
To find the voltage drop across the 30-ohns resistor, use
V = Itotal × (combined resistance of 40 30)
= 0.25 A × 17.14 ohms = 4.285 volts
so the current through the 30-ohm resistor is
I = (voltage drop)/30-ohms
= (4.285 V)/(30 ohms)
= 0.143 A
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Answer:
W = ½ m v²
Explanation:
In this exercise we must solve it in parts, in a first part we use the conservation of the moment to find the speed after the separation
We define the system formed by the two parts of the rocket, therefore the forces during internal separation and the moment are conserved
initial instant. before separation
p₀ = m v
final attempt. after separation
= m /2 0 + m /2 v_{f}
p₀ = p_{f}
m v = m /2
v_{f}= 2 v
this is the speed of the second part of the ship
now we can use the relation of work and energy, which establishes that the work is initial to the variation of the kinetic energy of the body
initial energy
K₀ = ½ m v²
final energy
= ½ m/2 0 + ½ m/2 v_{f}²
K_{f} = ¼ m (2v)²
K_{f} = m v²
the expression for work is
W = ΔK = K_{f} - K₀
W = m v² - ½ m v²
W = ½ m v²