Answer:
Uncorrected values for
For circuit P
R = 2.4 ohm
For circuit Q
R = 2.4 ohm
Corrected values
for circuit P
R = 12 OHM
For circuit Q
R = 2.3 ohm
Explanation:
Given data:
Ammeter resistance 0.10 ohms
Resister resistance 3.0 ohms
Voltmeter read 6 volts
ammeter reads 2.5 amp
UNCORRECTED VALUES FOR
1) circuit P
we know that IR =V
2) circuit Q
R = 2.4 ohm as no potential drop across ammeter
CORRECTED VALUES FOR
1) circuit p
IR = V
R= 12 ohm
2) circuit Q
R = 2.3 ohm
(1500 rev/min)(min / 60 s) / (3.0 s) = 8.33 rev/s²
<span>(B) </span>
<span>(1/2)(8.33 rev/s²)(3.0 s)² = 37.5 rev </span>
<span>(C) </span>
<span>(1500 rev/min)(min / 60 s)[2π(0.12 m) / rev] = 18.8 m/s</span>
The formula for finding the volume of a cylinder is V=πr2h
5ft is two times the 10ft
Answer:
B. 0.1 meters/second/second in the same direction of travel.
Explanation:
Acceleration is the rate of change of velocity. Acceleration is a vector quantity.
a=Δv/Δt
=(v₂-v₁)/(t₂-t₁)
v₁=4 m/s
v₂=6 m/s
t₁=0 s
t₂=20 s
a=(6m/s-4m/s)/(20s-0)
= 0.1 m/s² in the same direction of travel.
Therefore acceleration =0.1 meters/second/second in the same direction of travel.
