The distance of separation between the two masses is 0.927 m.
<h3>Gravitational force:</h3>
This is the force that exists between two masses in the universe.
To calculate the distance of separation of the masses, we use the formula below.
- F = GMm/r².............. Equation 1
Where:
- F = Gravitational force
- m = First mass
- M = Second mass
- G = Universal constant
- r = distance of seperation.
Make r the subject of the equation.
- r = √(GMm/F)................... Equation 2
From the question,
Given:
- F = 3.3×10⁻⁷ N
- m = 61 kg
- M = 75 kg
- G = 6.69×10⁻¹¹ Nm²/kg²
Substitute these values into equation 2
- r = √(61×75×6.69×10⁻¹¹)/(3.3×10⁻⁷)
- r = 0.927 m
Hence, The distance of separation between the two masses is 0.927 m
Learn more about Gravitational force here: brainly.com/question/11359658
Answer:
K.E = 5.53 eV = 8.85 x 10⁻¹⁹ J
Explanation:
First we calculate the energy of photon:
E = hc/λ
where,
E = Energy of Photon = ?
h = Plank's Constant = 6.626 x 10⁻³⁴ J.s
c = speed of light = 3 x 10⁸ m/s
λ = wavelength = 120 nm = 1.2 x 10⁻⁷ m
Therefore,
E = (6.626 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(1.2 x 10⁻⁷ m)
E = (16.565 x 10⁻¹⁹ J)(1 eV/1.6 x 10⁻¹⁹ J)
E = 10.35 eV
Now, from Einstein's Photoelectric equation we know that:
Energy of Photon = Work Function + K.E of Electron
10.35 eV = 4.82 eV + K.E
K.E = 10.35 eV - 4.82 eV
<u>K.E = 5.53 eV = 8.85 x 10⁻¹⁹ J</u>
Answer:
0.34148 m
Explanation:
= Resistivity of tungsten = 
d = Diameter = 0.0018 inch
r = Radius = 
= Temperature coefficient of tungsten = 
Power is given by
We have the equation
![R_2=R_1[1+\alpha(T_2-T_1)]\\\Rightarrow R_1=\dfrac{R_2}{1+\alpha(T_2-T_1)}\\\Rightarrow R_1=\dfrac{144}{1+0.0045(2550-25)}\\\Rightarrow R_1=11.64812\ \Omega](https://tex.z-dn.net/?f=R_2%3DR_1%5B1%2B%5Calpha%28T_2-T_1%29%5D%5C%5C%5CRightarrow%20R_1%3D%5Cdfrac%7BR_2%7D%7B1%2B%5Calpha%28T_2-T_1%29%7D%5C%5C%5CRightarrow%20R_1%3D%5Cdfrac%7B144%7D%7B1%2B0.0045%282550-25%29%7D%5C%5C%5CRightarrow%20R_1%3D11.64812%5C%20%5COmega)
Resistance is given by
The length of the filament is 0.34148 m
The process that explains why one part of the earth's surface is arid and dry and a nearby part is lush and wet is areal differentiation. It is<span> an approach to geography that shows </span>the dependence of the distribution of physical and human phenomena and the relation to each other from the physical location. Areal integration on the other hand is the approach that studies how places interact with each other.
