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DIA [1.3K]
2 years ago
5

The basketball coach tells his team to run sprints back and forth across the court, which is 30 m long. They start at the left e

nd of the court, run back and forth 6 times, then end back at the left end of the court where they began.
What distance did they run?
What is their displacement?
Physics
1 answer:
sp2606 [1]2 years ago
5 0

Distance is the total length of an object's path. Displacement is the overall change in position, ie. how far an object is from its initial position.


The court is 30 m long, so a path going back and forth once is 60 m long. Going along this path 6 times totals 360 m.


The end point is the same as the starting point, so the displacement is 0 m.

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The relationship between charge and current is:

i = \frac{Q}{t}

where

i is the current

Q is the charge

t is the time

Therefore, the current is the rate of change of the charge passing through a given point over time.

This means that for a graph of charge over time, the current is just equal to the slope of the graph.

For the graph in this problem:

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\frac{50-0}{2-0}=25 C/s

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therefore the current is

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The figure attached show these values plotted on a graph.

2) 15 \mu C

The previous equation can be rewritten as

Q = i t

This equation is valid if the current is constant: if the current is not constant, then the total charge is simply equal to the area under a current vs time graph.

Here we have the current vs time graph, so we gave to find the area under it.

The area of the first triangle is:

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While the area of the second square is

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So, the total area (and the total charge) is

Q=A_1 +A_2 = 5\cdot 10^{-6} + 1\cdot 10^{-5} = 1.5\cdot 10^{-5}C=1.5 \mu C

3 0
3 years ago
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