Answer:
The magnification of an astronomical telescope is -30.83.
Explanation:
The expression for the magnification of an astronomical telescope is as follows;
![M=-\frac{f_o}{f_e}](https://tex.z-dn.net/?f=M%3D-%5Cfrac%7Bf_o%7D%7Bf_e%7D)
Here, M is the magnification of an astronomical telescope,
is the focal length of the eyepiece lens and
is the focal length of the objective lens.
It is given in the problem that an astronomical telescope having a focal length of objective lens 74 cm and whose eyepiece has a focal length of 2.4 cm.
Put
and
in the above expression.
![M=-\frac{74}{2.4}](https://tex.z-dn.net/?f=M%3D-%5Cfrac%7B74%7D%7B2.4%7D)
M=-30.83
Therefore, the magnification of an astronomical telescope is -30.83.
Answer:
Jolt can expect to replace 160 units.
Explanation:
given data:
standard deviation 1.7
average lfe of connectors = 18.2 months
number of connectors = 5000
![z(19) = \frac{(19-18.2)}{1.7}](https://tex.z-dn.net/?f=z%2819%29%20%3D%20%5Cfrac%7B%2819-18.2%29%7D%7B1.7%7D)
z(19) = 0.4706
P(x< 19) = P(z< 0.4706)
P(x< 19) = 0.6810 from z table
therefore 68.1% fails within 19 months.
hence 0.3190 {100-68.1} will fail during that period.
number of unit of Jolt that need to be replace, on average is 0.319*500 = 160 units.
The answer is D. disorganized
1000000
Explanation
No equation for the following question was given