Please help me with these 3 questions!!
1 answer:
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The force constant of the spring is approximately 24.038 newtons per meter.
As we are talking about Simple Harmonic Motion. In this exercise we need to determine the Spring Constant (), in newtons per meter, from the equation of the Period (
), in seconds, which is described below:
(1)
Where is the mass of the moving element, in kilograms.
If we know that and
, then the spring constant of the spring is:
The force constant of the spring is approximately 24.038 newtons per meter.
Please see this question related to Simple Harmonic Motion for further details: brainly.com/question/17315536
The work done by the unstretched spring is 5 J.
<h3>What is the Hooke's law?</h3>Hooke's law states that the extension of a given material is directly proportional to the force applied as log as the elastic limit is not exceeded. Thus we have to know that; F = Ke
F = force applied
K = force constant
e = extension
Using the graph;
K = F/e
F = 200N
e = 5 cm or 5 * 10^-2 m
K = 200N/ 5 * 10^-2 m
K = 4000 N/m
Now;
Work = 1/2Ke^2
Work = 0.5 * 4000 N/m * (5 * 10^-2 m)^2
Work = 5 J
Learn more about Hooke's law:brainly.com/question/13348278
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Answer:
Explanation:
The <u>centripetal acceleration</u> of an object moving in a uniform circular path is given by the following equation:
(1)
Where:
is the tangential velocity
is the radius of the circle
On the other hand, the tangential velocity is expressed as:
(2)
Where is the angular velocity, which can be found knowing the child makes 5 revolutions in 13.4s:
(3)
Substituting (3) in (2):
(4)
(5)
Substituting (5) in (1):
(6)
Finally: