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lutik1710 [3]
3 years ago
6

I need the answers to these questions if u dont mind

Physics
1 answer:
Nonamiya [84]3 years ago
3 0
there’s no photo. brainly hasent been working for me today so not sure
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Question 3 of 10
Stels [109]

Answer:

30N

Explanation:

6 0
3 years ago
A 0.80-kg soccer ball experinces an impulse of 25 N x s . Determine the momentum change of the soccer ball.
borishaifa [10]

If the impulse is 25 N-s, then so is the change in momentum.
The mass of the ball is extra, unneeded information.

Just to make sure, we can check out the units:

<u>Momentum</u> = (mass) x (speed) = <u>kg-meter / sec</u>

<u>Impulse</u> = (force) x (time) = (kg-meter / sec²) x (sec) = <u>kg-meter / sec</u> 


3 0
4 years ago
Read 2 more answers
What happens to an atom if the electrons in the outer shell are altered?
maxonik [38]

Answer:

NUCLEAR BOMB

Explanation:

3 0
3 years ago
Read 2 more answers
Please help!!!!!!!! 25 points
Archy [21]

Answer:

B: beaks, finches.

Explanation:

Beaks, finches. This is because he noticed that fruit-eating finches had beaks similar to parrots, while finches that ate insects had narrow beaks. The difference in their beaks is due to adapting to different environments which causes them to evolve into different species of finches.

7 0
3 years ago
Read 2 more answers
calculate the magnitude of the electric field intensity in vacuum at a distance of 20 cm from a charge of 5 * 10 raise to power
forsale [732]

Answer:

1.1259*10^9 Newton per Columb

Explanation:

the magnitude of the electric field intensity can be calculated using the expresion below;

E=Kq/r^2

Where k= constant

q= electric charge

r=distance= 2cm= 20*10^-2m( we convert to m for unit consistency

:,K=59*10^9 Columb

If we substitute the value into above formula we have

E=(9*10^9)*(5*10^-3)/(20*10^-2)^2

=1.1259*10^9 Newton per Columb

Therefore,the magnitude of the electric field intensity in vacuum at a distance of 20 cm is 1.1259*10^9 Newton per Columb

3 0
3 years ago
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