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lesantik [10]
3 years ago
11

6. A boat with speed of 1.20 km/h relative to the water is heading for a dock 2.29

Physics
1 answer:
Lilit [14]3 years ago
3 0

Answer: 87 min

Explanation:

The speed of the boat S_{boat} will be its speed relative to the river S_{boat-river} plus the the speed of the river S_{river}:

S_{boat}=S_{boat-river}+S_{river} (1)

S_{boat}=1.20 km/h+0.384 km/h (2)

S_{boat}=1.584 \frac{km}{h} (3)

On the other hand, the speed of the boat is given by a relation between its traveled distance d and the time t:

S_{boat}=\frac{d}{t} (4)

Isolating t and knowing d=2.29 km:

t=\frac{d}{S_{boat}} (5)

t=\frac{2.29 km}{1.584 \frac{km}{h}} (6)

t=1.445 h \frac{60min}{1 h}=86.74 min \approx 87 min (7)

Hence the time in minutes is 87 min.

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Answer:

B-C

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Explanation:

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3 years ago
A river flows due east at 1.70 m/s. A boat crosses the river from the south shore to the north shore by maintaining a constant v
ad-work [718]

Answer:

a)

v = 14.1028 m/s  

∅ = 83.0765° north of east

b)

the required distance is 40.98 m

Explanation:

Given that;

velocity of the river u = 1.70 m/s

velocity of boat v = 14.0 m/s

Now to get the velocity of the boat relative to shore;

( north of east), we say

a² + b² = c²

(1.70)² + (14.0)² = c²

2.89 + 196 = c²

198.89 = c²

c = √198.89

c = 14.1028 m/s  

tan∅ = v/u = 14 / 1.7 =  8.23529

∅ = tan⁻¹ ( 8.23529 ) = 83.0765° north of east

Therefore, the velocity of the boat relative to shore is;

v = 14.1028 m/s  

∅ = 83.0765° north of east

b)  

width of river = 340 m,

ow far downstream has the boat moved by the time it reaches the north shore in meters = ?

we say;

340sin( 90° - 83.0765°)

⇒ 340sin( 6.9235°)

= 40.98 m

Therefore, the required distance is 40.98 m

5 0
2 years ago
Use the slit example to explain why you can hear a noise in another room through an open door.
defon
Because the wall reflects sound waves to your ears bouncing off of the walls, even if it's in another room.
8 0
3 years ago
There is a seasaw that's holding two men. The seesaw has a length of 18m that can pivot from a point at its center. Man 1 has a
Alex

Answer:

Distance=  2.3864m

Explanation:

So that the balance is in equilibrium parallel to the floor, we must match the moment each man makes with respect to the pivot point.

In many cases the point of application of force does not coincide with the point of application in the body. In this case the force acts on the object and its structure at a certain distance, by means of an element that transfers that action of this force to the object.

This combination of force applied by the distance to the point of the structure where it is applied is called the moment of force F with respect to the point. The moment will attempt a rotation shift or rotation of the object. The distance from the force to the point of application is called the arm.

Mathematically it is calculated by expression:

M= F×d

The moment caused by the first man is:

M1= 75kg × (9.81m/s²) × 1.75m= 1287.5625 N×m

The moment caused by the second man must be equal to that caused by the first by which:

M2= 1287.5625 N×m= 55kg × (9.81m/s²) × distance ⇒

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At this distance from the pivot point, the second should sit down so that the balance is balanced parallel to the ground.

3 0
2 years ago
What is the de Broglie wavelength of an object with a mass of 2.50 kg moving at a speed of 2.70 m/s? (Useful constant: h = 6.63×
xxMikexx [17]

Answer:

9.82 × 10^{-35} Hz

Explanation:

De Broglie equation is used to determine the wavelength of a particle (e.g electron) in motion. It is given as:

λ = \frac{h}{mv}

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Given that: h = 6.63 ×10^{-34} Js, m = 2.50 kg, v = 2.70 m/s, the wavelength, λ, can be determined as follows;

λ = \frac{h}{mv}

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 = 9.8222 × 10^{-35}

The wavelength of the object is 9.82 × 10^{-35} Hz.

4 0
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