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2 years ago

Which scenario involves acceleration?

1 answer:

4 0

Acceleration is caused when any force is applied to any moving object. This force can be an electric force, repulsion force, gravity, friction, etc .

And, force = mass x acceleration

This is the relationship between the force applied, the mass of the body on which force is applied and the acceleration.

Acceleration is applied to moving objects only because, as velocity = distance/time. Similarly, acceleration = velocity/time

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12. A rocket, initially at rest on the ground, accelerates vertically. It accelerates uniformly until it

vodomira [7]

Answer:

We kindly invite you to read carefully the explanation and check the image attached below.

Explanation:

According to this problem, the rocket is accelerated uniformly due to thrust during 30 seconds and after that is decelerated due to gravity. The velocity as function of initial velocity, acceleration and time is:

$v_{f} = v_{o}+a\cdot (t-t_{o})$ (1)

Where:

$v_{o}$ - Initial velocity, measured in meters per second.

$v_{f}$ - Final velocity, measured in meters per second.

$a$ - Acceleration, measured in meters per square second.

$t_{o}$ - Initial time, measured in seconds.

$t$ - Final time, measured in seconds.

Now we obtain the kinematic equations for thrust and free fall stages:

Thrust ( $v_{o} = 0\,\frac{m}{s}$ , $a = 30\,\frac{m}{s^{2}}$ , $t_{o} = 0\,s$ , $0\,s\le t< 30\,s$ )

$v = 30\cdot t$ (2)

Free fall ( $v_{o} = 900\,\frac{m}{s}$ , $a = -9.807\,\frac{m}{s}$ , $t_{o} = 30\,s$ , $30\,s \le t \le 120\,s$ )

$v = 900-9.81\cdot (t-30)$ (3)

Now we created the graph speed-time, which can be seen below.

5 0

2 years ago

Suppose that the Mars orbiter was to have established orbit at 155 km and that one group of engineers specified this distance as

MAXImum [283]

Answer:

108 km

Explanation:

The conversion factor between meters and feet is

1 m = 3.28 ft

So the second altitude, written in feet, can be rewritten in meters as

$h_2 = 1.55 \cdot 10^5 ft \cdot \frac{1}{3.28 ft/m}=4.7\cdot 10^4 m$

or in kilometers,

$h_2 = 47 km$

the first altitude in kilometers is

$h_1 = 155 km$

so the difference between the two altitudes is

$\Delta h = 155 km - 47 km = 108 km$

8 0

3 years ago

I don't hang out with girls so if you are a boy and you want to be friend say hi to me

MatroZZZ [7]

Answer:

Uh No thanks but make me brainiest!

Explanation:

4 0

2 years ago

Read 2 more answers

What stands for sound navigation and ranging

anastassius [24]

Sonar, originally an <span>acronym for SOund Navigation And Ranging
</span>a technique that uses sound<span> propagation.</span>

6 0

3 years ago

You step onto a hot beach with your bare feet. A nerve impulse, generated in your foot, travels through your nervous system at a

Masteriza [31]

Answer:

Explanation:

Speed = distance / time

Given speed = 127 m/s .

distance = 1.58 m

time = ?

Putting the values in the formula

127 m/s = 1.58 m / time

time = 1.58 / 127 s

= 12.44 ms .

8 0

2 years ago