Two circles<span> of </span>radius<span> 4 are </span>tangent<span> to the </span>graph<span> of y^</span>2<span> = </span>4x<span> at the </span>point<span> (</span>1<span>, </span>2<span>). ... I know how to </span>find<span> the </span>tangent<span> line from a circle and a given </span>point<span>, but ... </span>2a2=42. a2=8. a=±2√2. Then1−xc=±2√2<span> and </span>2−yc=±2√2. ... 4 from (1,2<span>), so you could </span>find these<span> centers, and from there the</span>equations<span> of the circle
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I think it yes the diagonals are congruent but I can’t really tell
Answer: 5.6 cm
Step by Step: I used the same formula as the question before and I got the answer for this question. When solving questions like this, you can work backwards from the problem and then solve
Answer:
Hey there!
We have an=a1(r^n-1), which is the formula for a geometric sequence.
The common ratio is 3, and 2 is the 1st term.
Thus, we have a1=2(3)^(n-1)
Hope this helps :)
Answer: 81 units²
Step-by-step explanation: To solve this problem, remember that the formula for the area of a square is 4s.
Therefore, since the perimeter of the given square is 36, we have 36 = 4s and dividing both sides by 4, 9 = s.
Now, remember that the formula for the area of a square is s² and since the length of a side of the given square is 9, we have (9)² or 81.
So the area of a square that has a perimeter of 36 is 81 units².
