Answer: The hydroxide ion concentration in a solution is ![1\times 10^{10}M](https://tex.z-dn.net/?f=1%5Ctimes%2010%5E%7B10%7DM)
Explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
pH is calculated by taking negative logarithm of hydrogen ion concentration.
![pH=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D)
![HCl\rightarrow H^++Cl^{-}](https://tex.z-dn.net/?f=HCl%5Crightarrow%20H%5E%2B%2BCl%5E%7B-%7D)
According to stoichiometry,
1 mole of
gives = 1 mole of
Thus
moles of
gives =
moles of
![K_w=[H^+][OH^-]](https://tex.z-dn.net/?f=K_w%3D%5BH%5E%2B%5D%5BOH%5E-%5D)
![10^{-14}=[1\times 10^{-4}][OH^-]](https://tex.z-dn.net/?f=10%5E%7B-14%7D%3D%5B1%5Ctimes%2010%5E%7B-4%7D%5D%5BOH%5E-%5D)
![[OH^-]=1\times 10^{10}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D1%5Ctimes%2010%5E%7B10%7DM)
Thus the hydroxide ion concentration in a solution is ![1\times 10^{10}M](https://tex.z-dn.net/?f=1%5Ctimes%2010%5E%7B10%7DM)
Answer:
W and Z
Explanation:
Atoms of the SAME element OR two atoms of DIFFERENT elements will form a MOLECULE.
E.g. 2 atoms of hydrogen + 1 atom of oxygen => 1 molecule of water. This 1 molecule of water can also be called a compound.
Also, 2 atoms of Oxygen can combine to form 1 molecule of Oxygen. This 1 molecule of Oxygen cannot be referred to as a compound.
Atoms of DIFFERENT elements form a COMPOUND.
Therefore, compounds are molecules, but molecules are not compounds.
Thus, the combination of atoms that will form a molecule, but not a compound is:
W(oxygen) + Z(oxygen) = molecule
Answer:
parts of outer space where there is no air or atoms
Explanation:
Matter is made up of atoms. Similar to how your cells make your body, atoms make up all and everything. This since outer spaces doesn't have atoms, it doesn't have matter as well (at least not the normal matter, it does have dark matter, which is a whole can of worms that should not be opened)
Answer: The density of glycerine is ![78.589\frc{pounds}{foot^3}](https://tex.z-dn.net/?f=78.589%5Cfrc%7Bpounds%7D%7Bfoot%5E3%7D)
Explanation: We are given density of glycerine in
which is ![1.26g/cm^3](https://tex.z-dn.net/?f=1.26g%2Fcm%5E3)
To convert t into
, we are given conversion rates:
454 grams = 1 pound
So, 1 gram will be equal to ![\frac{1}{454}pounds](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B454%7Dpounds)
Similarly,
![28317cm^3=1foot^3](https://tex.z-dn.net/?f=28317cm%5E3%3D1foot%5E3)
So,
will be equal to ![\frac{1}{28317}foot^3](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B28317%7Dfoot%5E3)
Converting the density of glycerin from
to
using above conversion rates, we get:
![\frac{1.26g}{cm^3}=(\frac{1.26}{454}\times \frac{28317}{1})\frac{pounds}{foot^3}](https://tex.z-dn.net/?f=%5Cfrac%7B1.26g%7D%7Bcm%5E3%7D%3D%28%5Cfrac%7B1.26%7D%7B454%7D%5Ctimes%20%5Cfrac%7B28317%7D%7B1%7D%29%5Cfrac%7Bpounds%7D%7Bfoot%5E3%7D)
![1.26g/cm^3=78.589pounds/foot^3](https://tex.z-dn.net/?f=1.26g%2Fcm%5E3%3D78.589pounds%2Ffoot%5E3)
Density of glycerin is ![78.589\frc{pounds}{foot^3}](https://tex.z-dn.net/?f=78.589%5Cfrc%7Bpounds%7D%7Bfoot%5E3%7D)
Answer:
a) 727.5 kJ
Explanation:
Step 1: Data given
Mass of the piece of copper = 6.22 kg
Initial temperature of the copper = 20.5 °C
Final temperature of the copper = 324.3 °C
Specific heat of copper = 0.385 J/g°C
Step 2:
Q = m*c*ΔT
⇒ with Q = heat transfer (in J)
⇒ with m = the mass of the object (in grams) = 6220 grams
⇒ with c = the specific heat capacity = 0.385 J/g°C
⇒ with ΔT = T2 -T1 = 324.3 - 20.5 = 303.8
Q = 6220 grams * 0.385 J/g°C * 303.8 °C
Q = 727509.9 J = 727.5 kJ
b) This heat capacity is the heat capacity given for a copper at a temperature of 25°C