Answer:
a. 473mL.
b. 79.38kg
c. 24.47lb of fat
d. 42.5g of N.
Explanation:
a. A qt is equal to 946mL. 0.500qt are:
0.500qt * (946mL / 1qt) = 473mL
b. 1lb is equal to 0.4536kg, 175lb are:
175lb *(0.4536kg / 1lb) = 79.38kg
c. The fat in kg of the athlete is:
74kg * 15% = 11.1kg of fat. In pounds:
11.1kg * (1lb / 0.4536kg) = 24.47lb of fat
d. The mass of nitrogen in the fertilizer is:
10.0oz * 15% = 1.5oz of N
1 oz is equal to 28.35g. 1.5oz are:
1.5oz * (28.35g / 1oz) = 42.5g of N
Answer:
O, N, C, H
Explanation:
Electronegativity of an element is the property that combines the ability of its atom to lose or gain electrons. It measures the relative tendency with which the atoms of the element attracts valence electrons in a chemical bond.
On the periodic table, Electronegativity increases across the period but decreases down a group.
To solve the given problem, let us use thE Pauling's table of electronegativities to compare the electronegativities of the elements.
On the table:
C = 2.5
H = 2.1
O = 3.5
N = 3.0
In terms of decreasing electronegativities, the atoms are arranged as:
O N C H
Answer: 4.74 moles
Explanation:

Moles of Ba=
Moles of Ba=
According to given balanced equation,
1 mole of Barium gives 2 moles of Li
Thus 2.37 moles of Barium gives=
Thus 4.74 moles of lithium will be produced by 135 g of barium.
Given ,
Mass of sample of cobalt = 27 g
density of sample of cobalt = 9g/cm^3
We know that ,
Density = mass of sample/volume of sample
From that relation ,
We can deduce the following as
Volume = mass of sample/density of sample
Hence , required volume of sample of cobalt = 27 g /9 g/cm^3 = 3 cm^3
The volume is