Answer:
2NaF + 1Br2 -> 2NaBr + 1F2
Explanation:
2NaF + 1Br2 -> 2NaBr + 1F2
I simply looked at both the left side and right side and saw there was only 1 F on the left side while there were 2 on the right side.
This means we have to make the left side have 2 F by multiplying NaF by 2.
However, this means there are now 2 Na as well. Going back to the right side, I multiplied NaBr by 2 so that there are 2 Na on both sides.
Now there are 2 Br on the right side. Checking back to the left side, there are also 2 Br, meaning this equation is now balanced.
The mass number is defined as the total number of protons and neutrons in an atom.
The climate near the equator is hot and dry, think of the Sahara desert. The climate near the north and south poles is very cold for almost the whole year.
One of the reasons for this is that as the earth orbits the sun the sun's rays are most intense for regions near the equator. Depending on the time of year, the sun's rays can be very weak near the poles, and if you are close enough to the poles there are days in deep winter when the sun does not even rise over the horizon!
<h2>
Hello!</h2>
The answer is:
There are 732.24 grams of Dinitrogen Pentoxide in 6.78 moles of the same compound.
<h2>
Why?</h2>
The dinitrogen pentoxide, or nitrogen pentoxide, is a rare salt that consists of anion and cations, and it's an important compound when preparing some kinds of explosives.
So, to answer the question, first, need to look for the molecular formula of the dinitrogen pentoxide, then, use it to calculate the mass in gram of 6.78 moles of the same compound.
The dinitrogen pentoxide formula is:
Where, the molar mass of each element are:
Calculating the molar mass of the compound, we have:
Now, calculating what is the mass of 6.78 of , we have:
So, there are 732.24 grams of Dinitrogen Pentoxide in 6.78 moles of the same compound.
Have a nice day!
Answer:
Distribution coefficient: 4.79
Explanation:
Distribution coefficient is the ratio between equilibrium concentration of non-aqueous phase and aqueous phase where both solvents are inmiscible. The equation for the problem is:
Distribution coefficient: Concentration in chloroform / Concentration in Water
<em>Concentration in water: 2.59mg / 30mL = 0.08633mg/mL</em>
<em>Concentration in chloroform: (15mg-2.59mg) / 30mL = 0.4137mg/mL</em>
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Distribution coefficient: 0.4137mg/mL / 0.08633mg/mL
<h3>Distribution coefficient: 4.79</h3>