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vichka [17]
3 years ago
5

Which is the correct Lewis structure for carbon tetrabromide (CBr4), in which a central carbon atom is bound to four atoms of th

e group 7A element bromine?
A



B



C



D

Chemistry
2 answers:
AveGali [126]3 years ago
8 0
The answer is b hope I helped
artcher [175]3 years ago
7 0

Answer:

B

Explanation:

Hello,

In this case, since carbon is in group IVA, it has four valence electrons so it needs four bonds to attain the octet. However, as carbon and bromine are bonded, carbon needs four bromines as each bromine provides only one electron for them to attain the octet as bormine has seven valence electrons for which it is in group VIIA. Therefore, the Lewis structure showing the four bonds and the seven free electrons of each bromine is B.

Best regards.

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Which change of phase is most likely occurring in the beaker
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What is the name of a solution whose concentration of solute is equal to the maximum concentration that is predicted from the so
faltersainse [42]

<u>Answer:</u> The correct answer is saturated solution.

<u>Explanation:</u>

For the given options:

Dilute solutions are defined as the solutions in which solute particles are present in less very amount than the solvent particles.

Unsaturated solutions are defined as the solutions where more and more of solute particles can be dissolved in the given amount of solvent.

Saturated solutions are defined as the solutions where no more solute particles can be dissolved in the solvent.  The concentration of the solute particles that can be dissolved in a solution is maximum.

Supersaturated solutions are defined as the solutions where more amount of solute particles are present than the solvent particles.

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7 0
3 years ago
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Is this correct? This is stoichiometry.
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Yes it’s is bc I said so
7 0
3 years ago
Cu + 2AgNO3 → Cu(NO3)2 + 2Ag
Eva8 [605]

Answer:

m_{Ag}=135.8gAg

Y=88.4\%

Explanation:

Hello there!

In this case, according to the described chemical reaction, it is possible to compute the theoretical mass of silver as mass via the 1:2 mole ratio of copper to silver and their atomic mass in the periodic table, in order to perform the following stoichiometric setup:

m_{Ag}=40.gCu*\frac{1molCu}{63.55gCu}*\frac{2molAg}{1molCu}*\frac{107.87gAg}{1molAg}\\\\   m_{Ag}=135.8gAg

Next, given the actual yield of 120 g, we compute the percent yield via:

Y=\frac{120g}{135.8g}*100\%\\\\Y=88.4\%

Regards!

4 0
2 years ago
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