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vichka [17]
3 years ago
5

Which is the correct Lewis structure for carbon tetrabromide (CBr4), in which a central carbon atom is bound to four atoms of th

e group 7A element bromine?
A



B



C



D

Chemistry
2 answers:
AveGali [126]3 years ago
8 0
The answer is b hope I helped
artcher [175]3 years ago
7 0

Answer:

B

Explanation:

Hello,

In this case, since carbon is in group IVA, it has four valence electrons so it needs four bonds to attain the octet. However, as carbon and bromine are bonded, carbon needs four bromines as each bromine provides only one electron for them to attain the octet as bormine has seven valence electrons for which it is in group VIIA. Therefore, the Lewis structure showing the four bonds and the seven free electrons of each bromine is B.

Best regards.

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Glucose (c6h12o6) has a single carbonyl group (-c=o) in its linear form. based on the number of oxygen atoms in glucose, how man
sveta [45]
Glucose is a hexose monosaccharide. It is one of the three major monosaccharides along with fructose and galactose. These are carbohydrates with a general formula of Cₓ(H₂O)ₓ, where x could be any number.

Now, you don't have to know the structural formula of the glucose to answer this. Just account all the elements in the glucose. You know that there are 6 oxygen atoms all in all. One of them belongs to the single carbonyl group. Consequently, that would mean that the remaining 5 oxygen atoms bond with hydrogen atoms to form 5 OH groups.

Just to be sure let us refer to the structural formula of glucose shown in the picture. It indeed has 5 OH groups.

3 0
3 years ago
Which of these takes place when a chemical change occurs?
zmey [24]

Answer:

In a chemical change, the atoms in the reactants rearrange themselves and bond together differently to form one or more new products with different characteristics than the reactants. When a new substance is formed, the change is called a chemical change.

Explanation:

7 0
3 years ago
Consider the reaction mg(oh)2(s)→mgo(s)+h2o(l) with enthalpy of reaction δhrxn∘=37.5kj/mol what is the enthalpy of formation of
Anni [7]
Answer is: -601,2 kJ/mol
Chemical reaction: Mg(OH)₂ → MgO + H₂O.
ΔHrxn = 37,5 kJ/mol.
ΔHf(Mg(OH)₂) = <span>−924,5 kJ/mol.
</span>ΔHf(H₂O) = <span>−285,8 kJ/mol.
</span>ΔHrxn -enthalpy of reaction.
ΔHf - enthalpy of formation.
<span>ΔHrxn=∑productsΔHf−∑reactantsΔHf. 
</span>ΔHf(MgO) = -924,5 kJ/mol - (-285,8 kJ/mol) + 37,5 kj/mol.
ΔHf(MgO) = -601,2 kJ/mol.
7 0
3 years ago
Read 2 more answers
The molecules CH4 and CH3Cl both have tetrahedral shapes. Why is CH4 nonpolar whereas CH3Cl is polar?
ruslelena [56]
Because in CH4 the valence electrons of Carbon are being pulled away from the nucleus with the same force (since all hydrogen has the same electronegativity).So charges are equally distributed throughout the atom and the atom is non-polar. In CH3Cl Cl has a different electronegativity than H, so charges aren't equally distributed and therefore the molecule is polar.
6 0
3 years ago
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Different isotopes of the same element emit light at slightly different wavelengths. A wavelength in the emission spectrum of a
Inessa [10]

Different isotopes of the same element emit light at slightly different wavelengths, the minimum number of slits  is mathematically given as

N=1820slits

<h3>What minimum number of slits is required to resolve these two wavelengths in second-order?</h3>

Generally, the equation for the wave is mathematically given as

d\ sin\ (\theta\ m) \ = \ m\  \lambda

Where the chromatic resolving power (R) is defined by

R\  =\ \lambda\ / \ d \  \lambda

R = nN,

Therefore

\lambda_1 \ = \  (656.45)(1 \ * \ 10^{-9})/1mm

\lambda_1= 656.45*10^{-9}

and

\lambda_2= (656.27)(1*10^{-9})/1mm

\\\\\lambda_2= 656.27*10^{-9}m

In conclusion, the minimum number of slits is required to resolve these two wavelengths in second-order

N\ =\ \dfrac{\lambda}{m\ d\ T\ }\\\\

Therefore

N\ =\ \dfrac{656.45 \ * \ 10^{-9}}{2\ * \ (0.18*10^{-9})}

N=1820slits

Read more about slits

brainly.com/question/24305019

#SPJ1

7 0
2 years ago
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