Answer:
a = 7.5 m / s²
Explanation:
For this exercise let's use Newton's second law, let's create a coordinate system with the x axis parallel to the plane and the y axis perpendicular to the plane
Y axis
N - W cos θ = 0
N = mg cos θ
X axis
W sin θ = m a
mg sin θ = m a
a = g sin θ
let's calculate
a = 9.8 cos 40
a = 7.5 m / s²
Answer:
201.06m/s
Explanation:
The solve this problem, we must understand that momentum must be conserved.
This implies that the starting momentum must be the same as the ending momentum. Since we are dealing with an inelastic collision:
Momentum of Plane + Momentum of truck = Momentum of plane + truck
Mp x Vp + Mt x Vt = V(Mp + Mt)
M is the mass
V is the velocity
t is truck
p is the plane
(540000 x 210) + (24000 x 0) = V (540000+24000)
113400000 = 564000V
V = 201.06m/s
Answer:
(a) W = 1329.5 J = 1.33 KJ
(b) ΔU = 24.27 KJ
Explanation:
(a)
Work done by the gas can be found by the following formula:
where,
W = Work = ?
P = constant pressure = (0.991 atm)() = 100413 Pa
ΔV = Change in Volume = 18.7 L - 5.46 L = (13.24 L)() = 0.01324 m³
Therefore,
W = (100413 Pa)(0.01324 m³)
<u>W = 1329.5 J = 1.33 KJ</u>
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(b)
Using the first law of thermodynamics:
ΔU = ΔQ - W (negative W for the work done by the system)
where,
ΔU = change in internal energy of the gas = ?
ΔQ = heat added to the system = 25.6 KJ
Therefore,
ΔU = 25.6 KJ - 1.33 KJ
<u>ΔU = 24.27 KJ</u>
The atoms of the element need to achieve chemical stability.